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yan [13]
3 years ago
15

Can someone plz help me with this problem I’m very frustrated

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
In a circle, the degree measure of an arc is the same as the measure of the central angle that intercepts it.

A full circle is 360 degrees.

Add all the measures and set equal to 360 degrees.

One angle measure is not given, but that angle has a mark and another angle has the same mark, so the angle whose measure is not give also measures -9x - 3.

-9x - 3 + x + 107 + (-6x + 8) + (-9x - 3) + (-13x - 1) = 360

-9x - 3 + x + 107 - 6x + 8 - 9x - 3 - 13x - 1 = 360

-36x + 108 = 360

-36x = 252

x = 252/(-36)

x = -7
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3 years ago
The distributive property 3(8-x)
PIT_PIT [208]

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x=8

Step-by-step explanation:

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8 0
4 years ago
Joan wants to reduce the area of her posters by one-third. Draw lines to match the original dimensions in the left column with t
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Answer:

1) 30\ in\ by\ 12\ in --------> 120\ in^{2}

2) 30\ in\ by\ 18\ in --------> 180\ in^{2}

3) 12\ in\ by\ 15\ in --------> 60\ in^{2}

4) 18\ in\ by\ 15\ in --------> 90\ in^{2}

Step-by-step explanation:

<u>Verify each case</u>

case 1) 30\ in\ by\ 12\ in

<em>Find the area with the original dimensions</em>

A=30(12)=360\ in^{2}

Reduce the area of the poster by one-third

360/3=120\ in^{2}

therefore

30\ in\ by\ 12\ in --------> 120\ in^{2}

case 2) 30\ in\ by\ 18\ in

<em>Find the area with the original dimensions</em>

A=30(18)=540\ in^{2}

Reduce the area of the poster by one-third

540/3=180\ in^{2}

therefore

30\ in\ by\ 18\ in --------> 180\ in^{2}

case 3) 12\ in\ by\ 15\ in

<em>Find the area with the original dimensions</em>

A=12(15)=180\ in^{2}

Reduce the area of the poster by one-third

180/3=60\ in^{2}

therefore

12\ in\ by\ 15\ in --------> 60\ in^{2}

case 4) 18\ in\ by\ 15\ in

<em>Find the area with the original dimensions</em>

A=18(15)=270\ in^{2}

Reduce the area of the poster by one-third

270/3=90\ in^{2}

therefore

18\ in\ by\ 15\ in --------> 90\ in^{2}

6 0
4 years ago
What is the value of c in the equation below?<br> 24.2²= abac
Bingel [31]

Answer:

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Step-by-step explanation:

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The normal notation for the square of a number n is not the product n × n, but the equivalent exponentiation n2, which is generally pronounced as "n square". The square number of the name results from the name of the form. The unit area is defined as the area of a unit square (1 × 1). Consequently, a square of lateral length n has the area n2.

Square numbers are not negative. Another way to say that an integer (not negative) is a square is to make its square root an integer again.

For example, √9 = 3, so, 9 is a quadratic number.

A positive integer that has no perfect square divisors other than one is called without a square.

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