All categories

3 years ago

I bet you BRAINLIEST you cant sing the rugrats theme song INATRUMENTAL

Mathematics

2 answers:

lidiya [134]3 years ago

6 0

Answer:

I cannn

Step-by-step explanation:

morpeh [17]3 years ago

3 0

Answer:

I CABBBBYV7VYNYBGIFVTBMIM

You might be interested in

Javier wants to buy a new video game that costs $62. Last week he saved $20 for the

Sloan [31]

Answer: 9h + 20 = 62

Step-by-step explanation:

he has 20 dollars now he needs 42 more so 9h is how much he earns multiplied by h how many hours he needs to work and you would add 20 onto that for the money he already saved and set that equal to the amount he needs

7 0

3 years ago

Please help me with this!! Thank you.

jolli1 [7]

tan blue gray

red red red

white white white

6 outfits

3 0

3 years ago

The mayor of renee's town chose 160 students from her school to attend a city debate. This amount is no more than 1/4 of the stu

azamat

The answer is d.
First you have to divide 160/ 1/4. So you would do 160/1 divided by 1/4. Because of keep, change and flip. (k.c.f) you would keep 160/1, change the division sign, then flip 1/4 to 4/1. Then you multiply 160/1*4/1. Then you would get 640. Hope this helped.

7 0

3 years ago

Find the limit of the sequence of partial sums whose general term is <img src="https://tex.z-dn.net/?f=a_n%3D%5Cfrac%7B100%5En%7

nasty-shy [4]

Answer:

Step-by-step explanation:

If ∑aₙ converges, then lim(n→∞)aₙ = 0.

Using ratio test, we can determine if the series converges:

If lim(n→∞) |aₙ₊₁ / aₙ| < 1, then ∑aₙ converges.

If lim(n→∞) |aₙ₊₁ / aₙ| > 1, then ∑aₙ diverges.

lim(n→∞) |(100ⁿ⁺¹ / (n+1)!) / (100ⁿ / n!)|

lim(n→∞) |(100ⁿ⁺¹ / (n+1)!) × (n! / 100ⁿ)|

lim(n→∞) |(100 / (n+1)|

0 < 1

The series converges. Therefore, lim(n→∞)aₙ = 0.

7 0

3 years ago

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

$(\left {{20} \atop {2}} \right. )$ $=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

$(\left {{3} \atop {2}} \right. )$ $=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$\frac{3}{190}\\ =0.01579\\=0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

4 0

2 years ago