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3 years ago

I need help again please help

Mathematics

1 answer:

makvit [3.9K]3 years ago

3 0

1 out 12 is the probability of it being raspberry-filled.

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I need help I don’t understand it

tiny-mole [99]

Shidddd lil buddy, try the 3rd one

4 0

3 years ago

the population of a town increases at a rate proportional to its population with an initial population of 1000. The corect initi

anyanavicka [17]

Answer:

This means that the correct initial value problem for the population p(t) as a function of time is is $P(0) = 1000$

Step-by-step explanation:

The population of a town increases at a rate proportional to its population:

This means that this situation is modeled by the following differential equation:

$\frac{dP}{dt} = kP$

In which k is the growth rate.

By separation of variables, the solution is given by:

$P(t) = P(0)e^{kt}$

In which P(0) is the initial population.

Initial population of 1000.

This means that the correct initial value problem for the population p(t) as a function of time is is $P(0) = 1000$

5 0

3 years ago

Select all the correct answers.<br> Which statements are true about function g?

erica [24]

Answer:

i need the question

Step-by-step explanation:

8 0

2 years ago

Solve step - by - step.<br> 5b-1>=-11<br><br> Plz help!

maks197457 [2]

It would -2 because you have to bring over the -1 on the other side of the equal sign. so you would do -11 plus 1 and you will get -10 then you would 5b÷-10 (simplify).5b=-10
b=-2

7 0

3 years ago

Read 2 more answers

I am very stuck with this

Bingel [31]

Answer:

see explanation

Step-by-step explanation:

To multiply the vector by a scalar, multiply each of the elements by the scalar.

To add 3 vectors add the corresponding elements of each vector

2a + 3b + 4c

= 2 $\left[\begin{array}{ccc}2\\3\\\end{array}\right]$ + 3 $\left[\begin{array}{ccc}-4\\1\\\end{array}\right]$ + 4 $\left[\begin{array}{ccc}3\\2\\\end{array}\right]$

= $\left[\begin{array}{ccc}4\\6\\\end{array}\right]$ + $\left[\begin{array}{ccc}-12\\3\\\end{array}\right]$ + $\left[\begin{array}{ccc}12\\8\\\end{array}\right]$

= $\left[\begin{array}{ccc}4-12+12\\6+3+8\\\end{array}\right]$

= $\left[\begin{array}{ccc}4\\17\\\end{array}\right]$

8 0

3 years ago