All categories

3 years ago

I need help again please help

Mathematics

1 answer:

makvit [3.9K]3 years ago

3 0

1 out 12 is the probability of it being raspberry-filled.

You might be interested in

Solve this quadratic equation using the quadratic formula. 5 - 10x - 3x2 = 0

horsena [70]

Answer:

x = (-5 ± 2√10) / 3

Step-by-step explanation:

5 − 10x − 3x² = 0

Write in standard form:

-3x² − 10x + 5 = 0

Solve with quadratic formula:

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ -(-10) ± √((-10)² − 4(-3)(5)) ] / 2(-3)

x = [ 10 ± √(100 + 60) ] / -6

x = (10 ± 4√10) / -6

x = (-5 ± 2√10) / 3

4 0

3 years ago

Read 2 more answers

Evaluate the following expression: p/-3 + (-8)= -8

aalyn [17]

P/-3+(-8)=-8
p/-3-8=-8
Add 8 to each side
p/-3-8+8=-8+8
p/-3=0
Multiply both side by 3
p/-3(3)=0(3)
p=0
Check:
p/-3+(-8)=-8
Substitute p with 0
0/-3+(-8)=-8
0-8=-8
-8=-8. As a result, p=0. Hope it help!

7 0

3 years ago

What is the solution to the square root of 3x-6 equals 3

Crazy boy [7]

Answer:

x=12

Step-by-step explanation:

8 0

3 years ago

What is the slope of the line on the graph

ella [17]

Answer:

The slope is 6

Step-by-step explanation:

The rise is 6 and the run is 1. 6/1

4 0

3 years ago

Read 2 more answers

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

3 years ago