Answer:
We validate that the formula to determine the translation of the point to its image will be:
A (x, y) → A' (x+4, y-1)
Step-by-step explanation:
Given
A (−1, 4)→ A' (3, 3)
Here:
- A(-1, 4) is the original point
- A'(3, 3) is the image of A
We need to determine which translation operation brings the coordinates of the image A'(3, 3).
If we closely observe the coordinates of the image A' (3, 3), it is clear the image coordinates can be determined by adding 4 units to the x-coordinate and subtracting 1 unit to the y-coordinate.
Thue, the rule of the translation will be:
A(x, y) → A' (x+4, y-1)
Let us check whether this translation rule validates the image coordinates.
A (x, y) → A' (x+4, y-1)
Given that A(-1, 4), so
A (-1, 4) → A' (-1+4, 4-1) = A' (3, 3)
Therefore, we validate that the formula to determine the translation of the point to its image will be:
A (x, y) → A' (x+4, y-1)
Answer:
68°
Step-by-step explanation:
22°+68°=90° ......
The correct answer to your question is
6.0828186e+62
Answer:
B
Step-by-step explanation:
15x-12<15x (distribute the 3) so it becomes 15x-13
-12<0 (group like terms)
I think there is a rule based in there, so Like:
T^1 : (x , y) ------> (x+3 , y+1)
T^2: (x, y ) -------> (x +3 +3 , y+1+1) = (x+6, y+2)
So I think T^3 should be:
T^3: (x, y) -------> ( x+3+3+3 , y+1+1+1) = (x+9, y+3)
So the answer should be the 2nd.