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Zina [86]
3 years ago
10

Find the third side. Round answer to tenths. answer : yds.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
4 0

Answer:

19 yds

Step-by-step explanation:

On the assignment in the sections it tells you how to find it.

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e-lub [12.9K]

41 there are 12 numbers take middle

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3 years ago
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Kenner and his friends went to the store and bough 2 bags of candy for $21 each. They decided to split the bill in 1/3. How much
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Two bags, $21 each means 2 x 21 = $42 total. 42/3 = $14
7 0
4 years ago
What is an equation of the line that passes through the point (-6,-4)(−6,−4) and is parallel to the line x+6y=12x+6y=12?
masya89 [10]

Answer:

x + 6y + 30 = 0

Step-by-step explanation:

x + 6y = 12

6y = -x + 12

y = -⅙x + 2

Slope: -⅙

y - (-4) = -⅙(x - (-6))

y + 4 = -⅙(x + 6)

-6y - 24 = x + 6

x + 6y + 30 = 0

4 0
4 years ago
Jaclyn plays singles for the varsity tennis team where she won the sudden death tie breaker point with a cross-court passing sho
podryga [215]

Answer:

Incomplete question

Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.

a. Determine the pre-collision momentum of the ball.

b. Determine the post-collision momentum of the ball.

c. Determine the momentum change of the ball.

Answer:

A. 1.5353kgm/s

B. 1.6963kgm/s

C. 0.161kgm/s

Step-by-step explanation:

A. The pre-collision momentum of the ball = mass of ball × velocity of ball

Mass of ball = 57.5g = 0.0575kg

Velocity of ball = 26.7m/s

Pre-collision momentum of ball = 0.0575×26.7

= 1.5353kgm/s

B. Post collision momentum of the ball = mass of ball × velocity of ball after impact

Velocity of ball after impact = 29.5m/s

Post collision momentum of ball after impact = 0.0575×29.5

= 1.6963kgm/s

C. Momentum change of ball = momentum after impact - momentum before imlact

= 1.6963kgm/s - 1.5353kgm/s

= 0.161kgm/s

7 0
3 years ago
Laws involving positive integral exponents to zero & negative integral exponents.
fiasKO [112]

Answer:

  • Both are correct

Step-by-step explanation:

<u>Paul used the following identities:</u>

  • a^{-b}=1/a^b
  • a^b*a^c=a^{b+c}

<u>Anthony used the identity:</u>

  • a^b/a^c= a^{b-c}
3 0
3 years ago
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