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2 years ago

Find the percent of change. Original: 80, new: 64

1 answer:

3 0

Hi there!

To find the percent of change we can use the following formula:
$\frac{new - old}{old} \times 100\%$

Let's fill in our data
$\frac{64 - 80}{80} \times 100\% =$

Subtract
$\frac{ - 16}{80} \times 100\% =$

Divide
$- 0.2 \times 100\%$

And finally multiply
$- 20\%$

Hence, the percent of change is negative 20%.
~ Hope this helps you!

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2 u + 12 < 23 0,1 d + 8 > 0 3 - 4 r > 7 13 < 2 z + 3 6 ≥ 9 - 0, 15 i

BartSMP [9]

Answer:

Part 1) $u< 5.5$

Part 2) $d > -80$

Part 3) $r < -1$

Part 4) $z>5$

Part 5) $i\geq 20$

Step-by-step explanation:

The question is

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

subtract 12 both sides

$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

subtract 8 both sides

$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

$-4r>7-3\\-4r>4$

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$r < -1$

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

$6-9\geq -0.15i\\-3\geq -0.15i$

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$20\leq i$

Rewrite

$i\geq 20$

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0

3 years ago

The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.

mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = $\frac{1}{2}(b_1+b_2)h$

where $b_1$ and $b_2$ are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = $\frac{1}{2}(11+12)\times 6$

= 69 m²

Area of the rectangle (2) = Length × Width

= 12 × 15

= 180 m²

Area of the trapezoid (3) = $\frac{1}{2}(12+10)\times 11$

= 121 m²

Now area of the wall = 69 + 180 + 121

= 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = $\frac{\text{Total area}}{\text{Area covered by one tin}}$

= $\frac{370}{25}$

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

= £105

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He will have more than enough because he only needs to cover 84.1425 square feet.

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