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mel-nik [20]
3 years ago
9

Help me in this plz....

Mathematics
1 answer:
solniwko [45]3 years ago
3 0

Answer:

70. 8x⁴

71. 3n - 10

72. a/5 + 12

Step-by-step explanation:

70. a number "x" raised to the fourth = x⁴

Product of 8 and x⁴ = 8 × x⁴

= 8x⁴

71. 3 times a number "n" = 3 × n = 3n

3n decreased by 10 = 3n - 10

72. Quotient of a number "a" and 5 = a/5

12 more than a/5 = a/5 + 12

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Find the slope of the line that passes through the pair of points
love history [14]

Answer:

\frac{5,805}{2812}

Step-by-step explanation:

To find the slope from two points you can use the following formula:

m = \frac{y -y_{1} }{x -x_{1} }

Now substitute the two sets of points (\frac{7}{20}, \frac{5}{19} ) and (\frac{5}{9}, \frac{11}{16})

Substitute the values like this:

y = \frac{5}{19}, y_{1} = \frac{11}{16}, x = \frac{7}{20} and x_{1} =\frac{5}{9}

Now you will need to simplify the following expression:

m = \frac{\frac{5}{19} -\frac{11}{16} }{\frac{7}{20}-\frac{5}{9} }

Make sure that denominators are the same before substracting:

m = \frac{\frac{-129}{304} }{\frac{-37}{180} }

when you divide with a fractional number you only need to flip the second fraction over (find its reciprocal). Then just multiply:

m = (\frac{-129}{304} })({\frac{-180}{37} } ) = \frac{5805}{2812}

5 0
3 years ago
Find the two square roots of each complex number by creating and solving polynomial equations.
son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

w₂=\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))=-1+i

2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

w₁=\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))= 2- 3i

w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

5) z = 21 − 20i  ⇒ r=29 θ= -0.8098 rad

w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁=\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))= 5 - 3i

w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

6 0
4 years ago
Can someone help me solve this please + ( − )2
Pavlova-9 [17]
-2

We know that a positive and a negative will end in a negative result. (+) (-) = (-)
4 0
3 years ago
Plz answer I really need it
satela [25.4K]
It’s option C I believe.
8 0
3 years ago
What is 15 percent of 50
gulaghasi [49]
15% x 50 = 7.5
You can search these up in a calculator or in google if you want. The answers should be online.
5 0
4 years ago
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