Option 2: 
is the correct answer.
Step-by-step explanation:
The radical expressions like these are simplified by using fractional exponents
given
![\frac{\sqrt{4}}{\sqrt[3]{4} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B4%7D%7D%7B%5Csqrt%5B3%5D%7B4%7D%20%7D)
Converting radicals into exponents
When there is no base the exponent is 1/2 and as the base is 3, the exponent will be 1/3
So
As the bases of numerator and denominator is same, the exponents can be subtracted
Hence,
Option 2: is the correct answer.
Keywords: Exponents, radicals
Learn more about radicals at:
#LearnwithBrainly
To solve this system by substitution, we must substitute in the value we are given for x in terms of y (the first equation) into the second equation. This is modeled below:
x = -8y - 15
2x + 5y = -8
2 (-8y - 15) + 5y = -8
Now, we should solve this new equation for y. To begin, we should use the distributive property to get rid of the parentheses on the left side of the equation and begin the simplification process.
-16y - 30 + 5y = -8
Next, we can combine like terms on the left side of the equation by adding together the two terms that both contain the variable y.
-11y - 30 = -8
Next, we should add 30 to both sides in order to move all of the constant (number) terms to the left side of the equation.
-11y = 22
After that, we should divide both sides of the equation by -11 in order to get the variable y alone.
y = -2
Now, we can substitute our value for y back into one of our original equations (it doesn't matter which one you choose; they will yield the same answer).
x = -8y - 15
x = -8(-2) - 15
To simplify, we should following the order of operations outlined by PEMDAS and compute the multiplication and then the subtraction.
x = 16 - 15
x = 1
Therefore, the answer to the system is x = 1 and y = -2, or (1,-2) when written as an ordered pair.
Hope this helps!
Answer:
90/4= 12.9
1*3/4= 0.75
Step-by-step explanation:
(-2^6)^(2/3) = -2^(6*2/3) = -2^(4) = -16
Shouldn't be an imaginary number though.
4318 ÷ 7 = 616.86 (rounded to the nearest hundredth)
