Suppose the number of bacteria are increasing exponentially, We can model the number of bacteria at a given time t, using the formula:
f(t)=ae(tk)
where, k=constant of proportionally and a=initial number;
thus;
f(t)=2000e(0.005t)
Therefore the population after 12 hours will be:
f(12)=2000e^(0.005*12)
f(12)=2,123.67=2,123 bacteria
Answer: (11, 7.5)
Step-by-step explanation:
((8, 12)+(14, 3))/2=
(8+14, 12+3)/2=
(22/2, 15/2)=(11, 7.5)
Answer: 30 grams
Step-by-step explanation:
The interquartile range is the range within the boxed areaa. You subtract the minimum value from the maximum value.
150 - 120 = 30
The probability of getting heads on the first toss is 1/2 .
Then, the probability of getting heads on the second toss is 1/2 .
Then, the probability of getting heads on the third toss is 1/2 .
The probability of all three things happening is ...
(1/2) x (1/2) x (1/2) = 1/8 = 0.125 = 12.5% .
Answer:
$537.60
Step-by-step explanation:
12% increase is the same as multiplying by 1.12, 480*1.12=537.60
