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4 years ago

Find the sum of 9x² - 6x + 7, 5-4 xand 6-3x²

Mathematics

1 answer:

puteri [66]4 years ago

3 0

Answer:

6x² - 10x + 11

Step-by-step explanation:

Step 1: Write expression

(9x² - 6x) + (5 - 4x) + (6 - 3x²)

Step 2: Combine like terms

6x² - 10x + 11

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Find the equation of a line with slope 1/2 and y intercept -1

Mrac [35]

If you use slope-intercept form, Y =mx+b

m is equal to the slope,
and b is the y intercept.

Y= (1/2)x+ (-1)

or
Y = (1/2)x-1

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3 years ago

What is equivalent to 1:1

aksik [14]

Answer: Hi your answer is

2:2 or 1000:1000

Step-by-step explanation:

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3 years ago

Read 2 more answers

Victoria has 2.50 pounds of bell peppers and the cost is $1.25. What is the price for 1 pound of bell peppers?

AleksAgata [21]

Answer:

The price of one pound of bell peppers is $0.6.

Step-by-step explanation:

This problem is equivalent to the following:

<em>"if 10 oranges cost $20, how much does 1 orange cost? "</em>

and the answer to that question is:

price of 1 orange = $20/ 10 oranges = $2 per orange.

Put simply, we divided the total price by the total number of items, and we shall do the same thing for the case of bell peppers:

price of 1 pound = $1.25/ 2.5 pounds = $0.5/ pound.

The price for 1 pound of bell peppers is $0.5.

8 0

4 years ago

A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t

Licemer1 [7]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which this amount changes over time is given by the ODE

$A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$

$A'(t)+\dfrac1{100}A(t)=15$

We're told that the tank initially starts with no salt in the water, so $A(0)=0$ .

Multiply both sides by an integrating factor, $e^{t/100}$ :

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}$
$\left(e^{t/100}A(t)\right)'=15e^{t/100}$
$e^{t/100}A(t)=1500e^{t/100}+C$
$A(t)=1500+Ce^{-t/100}$

Since $A(0)=0$ , we have

$0=1500+C\implies C=-1500$

so that the amount of salt in the tank over time is given by

$A(t)=1500(1-e^{-t/100})$

After 10 minutes, the amount of salt in the tank is

$A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}$

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3 years ago

Julianne drew the line segment below. Use your ruler to measure the segment to the nearest fourth inch

kicyunya [14]

Answer:need help

Step-by-step explanation:

7 0

3 years ago

Find the sum of 9x² - 6x + 7, 5-4 xand 6-3x²​

Find the sum of 9x² - 6x + 7, 5-4 xand 6-3x²