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Snowcat [4.5K]
3 years ago
14

Hi please help I have no idea how to even start my work, someone help!!!.

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

x is greater than -3 and it is also less than or equal to 2

-3 < x  ≤ 2

Step-by-step explanation:

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Using the substitution P=1/x and Q=1/y.
erma4kov [3.2K]

Step-by-step explanation:

2p + q = 3 \\ p - 5q = 7 \\  \\ multiply \: the \: second \: equation \: by \: 2 \\  2p - 10q = 14 \\ 2p - 10q - (2p + q) = 14 - 3 \\ 2p - 10q - 2p - q = 11 \\  - 11q = 11 \\ q =  - 1 \\  \\ 2p + q = 3 \\ 2p - 1 = 3 \\ 2p = 4 \\ p  = 2

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3 years ago
What is the answer for ½+¼⅝​
Sphinxa [80]

Answer:

1 3/8

SOLUTION

add \:  \frac{1}{2}  +   \frac{1}{4} +  \frac{5}{8}

= \frac{4 + 2 + 5}{8}

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7 0
3 years ago
Read 2 more answers
Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



7 0
4 years ago
Read 2 more answers
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Triangle inequalities? Write &gt;, &lt;, =, or NC?
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