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Minchanka [31]
3 years ago
12

Please help I’ll mark you as brainliest if correct

Mathematics
1 answer:
mylen [45]3 years ago
3 0

Answer:

A.I dont know but I think its 26 B. 64 inches if you add 38 and 26 you will get 64

Step-by-step explanation:

because 38 inches - 12 inches = 26 inches

I hope this helped!

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A storekeeper increased the price of hats by 5%. Write an equation to calculate the increase of the total cost, c, when the pric
Naddik [55]

Answer:

c = 1.05p

Step-by-step explanation:

the price of the hat before the increase was 100%, after the increase it becomes 100 + 5% = 105%. Representing it as a decimal becomes 1.05p

Let illustrate with an example.

The price of a hat was $100, after the 5% increase. the cost of the hat becomes

100 + (0.05 x 100) = 105

To find the percentage increase

divide 105 by 100 and subtract 1

(105/100) - 1 = 1.05

3 0
3 years ago
Classify the function as a linear or quadratic and identify the quadratic, linear, and constant terms. y=(3x+4)(-2x-3)
Troyanec [42]

Answer:

The function is quadratic

Step-by-step explanation:

I just took the quiz and I Had a passing score

3 0
3 years ago
Record the data on a line plot 20,17,20,17,18,17,20,18,16
jek_recluse [69]

Answer:

ex or x times y

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
What is the answer A B C or D
Vanyuwa [196]

To solve this question, use the Cube surface area formula

Area = 6a^2 in which a = edge.

edge = 8.5

Area = 6(8.5)²

Simplify. Follow PEMDAS

Area = 6(72.25)

Area = 433.5

(C) 433.5 in² is your answer

hope this helps

3 0
3 years ago
Read 2 more answers
300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
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