Please help ASAP RN

Solve c= 8a-3b for a

Vesnalui [34]

Answer:

(c+3b)/8 = a

Step-by-step explanation:

c= 8a-3b

Add 3b to each side

c+3b= 8a-3b+3b

c+3b = 8a

Divide each side by 8

(c+3b)/8 = 8a/8

(c+3b)/8 = a

6 0

3 years ago

A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0

3 years ago

Hello there!

otez555 [7]

Answer:

24 Domain: s>=2 or s<=-2

25. 3x^2 +14x +10

26. x^2 -2x+5

Step-by-step explanation:

24. Domain is the input or s values

square roots must be greater than or equal to zero

s^2-4 >=0

Add 4 to each side

s^2 >=4

Take the square root

s>=2 or s<=-2

25. f(g(x)) stick g(x) into f(u) every place you see a u

f(u) = 3u^2 +2u-6

g(x) = x+2

f(g(x) = 3(x+2)^2 +2(x+2) -6

Foil the squared term

= 3(x^2 +4x+4) +2x+4-6

Distribute

= 3x^2 +12x+12 +2x+4-6

Combine like terms

=3x^2 +14x +10

26 f(g(x)) stick g(x) into f(u) every place you see a u

f(u) = u^2+4

g(x) = x-1

f(g(x) = (x-1)^2 +4

Foil the squared term

= (x^2 -2x+1) +4

= x^2 -2x+5

7 0

3 years ago

An electrician charges $40 to come to your house she also charges $55 for each hour that she works the electrician charges you a

s2008m [1.1K]

First lets remove the initial fee
$190 - 40 = 150$
150 is how much she is charging you per hour.
If each hour is 55, lets divide 150 by 55.
$150 \div 55 = 2.7$
She charged you for 2.7 hours (almost 3) of service

3 0

3 years ago

four times the greater of two consectutive integers is 18 more than three times the lesser integer .what are the intergers?

shutvik [7]

The intergers or 4 and 2

7 0

3 years ago