<span>the sum of three consecutive odd integers is 69. Find the integers.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:</span>2x-1 + 2x+1 + 2x+3 = 69<span>
</span><span>6x + 3 = 69
2x + 1 = 23
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So 2x-1 = 21
And 2x+3 = 25
</span><span>let:
x be the first odd integer
x + 2 be the 2nd odd integer
x + 4 be the 3rd odd integer
solution:
1st odd integer + 2nd odd integer + 3rd odd integer = 69
x + (x+2) + (x+4)= 69
</span>
<span>3x + 6 = 69
3x = 69 - 6
3x = 63 (dividing both sides by three)
x = 21
_______________________________________
x=21
x+2=23
x+4=25
therefore, the 1st integer is 21, the 2nd is 23 and the 3rd is 25..</span>
Answer:
Option 2 would be the best answer
Step-by-step explanation:
In this case, a= 3x and b= 4
Since there is a power 2, it is a quadratic equation not a linear equation.
Answer:
C. 35
Step-by-step explanation:
I just went through all the numbers, multiplied them by 2, because you start with x which is 50, and the goal is to get to 120 with 50 and a number multiplied by two, so I tried 35 which would be 70 when multiplied by two, then added 50, which would make 120.
Answer:
54 / 18 = 3
42 / 14 = 3
You can have 3 equal arrangements of 18 roses and 14 tulips
Step-by-step explanation:
486, (1/3) times 486 = 162, (1/3) times 162 = 54, (1/3) times 54 = 18
so answer is D
