Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
Let the only force acting on the ball is the gravity (free-failing) and the ball was initially stationary
vo = 0
s = vot + 1/2 gt^2
s = 1/2 x 10 x (2.2) ^2 = 24.2 m
A) .10 d + .25 q = 7.75
B) d + q = 40
Multiplying B) by -.10
B) -.10d -.10q = -4.0
Then adding this to A)
A) .10 d + .25 q = 7.75
.15q = 3.75
Quarters = 25
Therefore, dimes = 15
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Double-Check
A) .10 d + .25 q = 7.75
A) .10 * 15 d + .25 * 25 = 7.75
A) 1.50 + 6.25 = 7.75
Correct!!
Answer:
The answer is option C
Step-by-step explanation:
sin C = opposite / hypotenuse
the opposite is 40
the Hypotenuse is 50
so
sin C = 40/50 = 4/5
Hope this helps you
