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Olin [163]
3 years ago
10

5% of 20= ? i really need help with this, someone help.

Mathematics
1 answer:
Mariana [72]3 years ago
8 0

Answer:

1

Step-by-step explanation:

<em><u>Use the clues given.</u></em>

We know that 5% is equal to 5/100 or .05. Using one of those numbers, we can find what the answer is.

<u><em>Multiply by 20.</em></u>

In this case, I will be using .05, just because it is the easiest. So, if we multiply .05 by 20, we will get 1.

Hope this helped,

Philip

Brainliest is always appreciated! <3

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Make a ratio, then cross multiply.

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30x=4x48
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Find the measure of x and y (3x-3) (4y+4) 60 degrees
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Answer:

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Step-by-step explanation:

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3 years ago
A car mechanic rounds a car's weight to the nearest thousand. He says the weight is 4,000 pounds. What is the least and the grea
serg [7]

Answer:

Step-by-step explanation:

Given that a car mechanic rounds a car's weight to the nearest thousand

By rounding off to nearest 1000, we mean we look at the last three digits. If these digits are 500 or greater, then we round the thousands digit up, and if they are less than 500, then we round down, keeping the thousand's digit the same.

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Example, 18765 is rounded off as 19000 while

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If two angles of a triangle have measures equal to the measures of two angles of another triangle, then the triangles are similar. Corresponding sides of similar polygons are in proportion, and corresponding angles of similar polygons have the same measure.

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3 years ago
Read 2 more answers
22. An employee joined a company in 2017 with a starting salary of $50,000. Every year this employee receives a raise of $1000 p
Setler79 [48]

Answer:

(a) The recurrence relation for the salary is

S_{n+1}=1.05*S_n+1000\\\\S_0=50000

(b) The salary 25 years after 2017 will be $217044.85.

(c) S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

Step-by-step explanation:

We can define the next year salary S_{n+1} as

S_{n+1}=S_n+1000+0.05*S_n=1.05*S_n+1000

wit S0=$50000

If we extend this to 2 years from 2017 (n+2), we have

S_{n+2}=1.05*S_{n+1}+1000=1.05*(1.05*S_n+1000)+1000\\S_{n+2} =1.05^2*S_n+1.05*1000+1000\\S_{n+2}=1.05^2*S_n+1000*(1.05^1+1)

Extending to 3 years (n+3)

S_{n+3}=1.05*S_{n+2}+1000=1.05(1.05^2*S_n+1000*(1.05^1+1))+1000\\\\S_{n+3}=1.05^3S_n+1.05*1000*(1.05^1+1)+1000\\\\S_{n+3}=1.05^3*S_n+1000*(1.05^2+1.05^1+1)

Extending to 4 years (n+4)

S_{n+4}=1.05*S_{n+3}+1000=1.05*(1.05^3*S_n+1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1.05*1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1000*(1.05^3+1.05^2+1.05^1+1.05^0)

We can now express a general equation for S_n (salary at n years from 2017)

S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n

The salary at 25 years from 2017 (n=25) will be

S_{25}=1.05^{25}S_0+1000*\sum_{0}^{24}1.05^i\\\\S_{25}=3.386*50000+1000*47.72=217044.85

8 0
4 years ago
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