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dedylja [7]
2 years ago
14

6+9=?

gn="absmiddle" class="latex-formula">
Mathematics
1 answer:
ELEN [110]2 years ago
4 0

Answer:

are u sure thet write the question right?

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The answer is a i’m pretty sure, if i’m incorrect then i’m sorry but i’m sure that it’s a :)
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What is 15 percent of 60
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3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
PLEASE HELP!!!!!!!!!!!!!
Naddik [55]

Answer:

Step-by-step explanation:

a) To find the length of diagonal XT, we can use the distance formula to get \sqrt{(-3-5)^{2}+(4-(-2))^{2}}=10

Since this is a rectangle, XT=YW, meaning YW=10 as well.

b) The area of a rectangle is given by length times width. The length is |-3-5|=8, and the width is |-2-4|=6. So the area is (8)(6)=48.

c) The perimeter is just 2(8+6)=28.

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2 years ago
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