Answer:
Step-by-step explanation:
Good luck
Answer:
C) The area of the landscape model is A = 40 sq ft.
Step-by-step explanation:
The original dimensions of the rectangular patio model is
Length = L
Width = W
Area of the patio model = LENGTH x WIDTH = L x W
⇒ A = L W ............. (1)
Now, the new area A" is enlarged by a factor of 2
⇒ The new Length = L" = (2 L)
The new Width = W" = (2 W)
So, AREA" = L" x W" = (2 L) x (2 W) = 4 (L W)
⇒ A " = 4 (L W)
But, L W = A .. from (1)
⇒ A" = 4 A
But, the area of the new enlarged patio is 160 square feet.
⇒ 160 sq ft = 4 x A
or, A = 160 / 4 =40 sq ft
⇒ A = 40 sq ft.
Hence, the area of the landscape model is A = 40 sq ft.
Answer:
15
Step-by-step explanation:
38/2.5=15.2
Round it to 15
Answer:
43.75 ft²
Step-by-step explanation:
= (l√(w/2)² + h²) + (w√(l/2)² + h²)
l & w become 3.5, and h becomes 6.
<em />
<em> </em>= (3.5√(3.5/2)² + 6²) + (3.5√(3.5/2)² + 6²)
<em>Step 1:Because this is a square pyramid, what you see above essentially becomes what you see below.</em>
<em />
= 2(3.5√(3.5/2)² + 6²)
<em>Step 2: Divide 3.5 by 2 to get 1.75.</em>
<em />
<em> </em>= 2(3.5√1.75² + 6²)
<em>Step 3: Square both 1.75 and 6 to get 3.0625 and 36 respectively.</em>
= 2(3.5√3.0625 + 36)
<em>Step 4: Add 3.0625 and 36 to get 39.0625.</em>
<em />
= 2(3.5√39.0625)
<em>Step 5: The square root of 39.0625 is 6.25.</em>
<em />
<em> </em>= 2(3.5 * 6.25)
<em>Step 6: Multiply 3.5 by 6.25 to get 21.875.</em>
<em />
= 2(21.875)
<em>Step 7: Multiply 2 by 21.875 to get 43.75.</em>
<em />
= 43.75 ft²
The lateral area of this pyramid is 43.75 ft².
<em />
<em />
Answer:

Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean
kilograms and standard deviation
kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and 
And the best way to solve this problem is using the normal standard distribution and the z score given by:

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:

So then the corresponding z scale would be:
