<span>2.8 x 10^6 N
We have 9.8 x 10^7 J or 9.8 x 10^7 kg*m^2/s^2 of work done through a distance of 35 meters. Since work is defined as force over distance, that means that:
F * 35m = 9.8 x 10^7 kg*m^2/s^2
Solving for F, gives
F * 35m = 9.8 x 10^7 kg*m^2/s^2
F = 9.8 x 10^7 kg*m^2/s^2 / 35m
F = 2.8 x 10^6 kg*m/s^2
F = 2.8 x 10^6 N
So the force exerted by the tugboat is 2.8x10^6 Newtons.</span>
We will have the following:
First, we solve both equations for y, that is:
&
From this we can see that they are parallel lines, that do not share any common points, so there is no solution for the system.
Answer:
103
Step-by-step explanation:
108+85+94+103+112+115+98+119+126+105+82+89=1236
1236/12=103
Answer:
x² + 9x + 8
Step-by-step explanation:
Step 1: FOIL
x² + 8x + x + 8
Step 2: Combine like terms
x² + 9x + 8
Answer:
y = 17(2)^x
Step-by-step explanation:
If the graph of y = ab^x goes through (0, 17), then
17 = ab*0, or a = 17
Then the function is y = ab^x with a = 17, or
y = 17*b^x and we must find b.
If the graph of y = 17*b^x also goes through (6, 1088), then the following must be true: 1088 = 17*b^6
which reduces to 64 = b^6
Taking the sixth root of both sides, we get 64^(1/6) = b, and so b = 2
Then the desired exponential function is
y = 17(2)^x
