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3 years ago

6 The radius of a circle is 36 millimeters.

Mathematics

2 answers:

love history [14]3 years ago

8 0

Answer:

G. 226 mm

Step-by-step explanation:

C=2(3.14)(36)

11111nata11111 [884]3 years ago

6 0

I agree that it is g

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0.23 divided by 5.05 explain with steps

Elden [556K]

Answer:

Step-by-step explanation:

\mathrm{Multiply\:the\:numerator\:and\:denominator\:by:}\:100

\mathrm{Multiply\:the\:quotient\:digit}\:\left(0\right)\:\mathrm{by\:the\:divisor}\:505

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3 years ago

The time to complete a standardized exam is approximately normal with a mean of 70 minutes & a standard deviation of 10 minu

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3 years ago

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18. what is the midpoint of PQ P(-2, 2.5), Q(1.4, 4)

scoray [572]

Mid point of the points PQ is (₋0.3 , 3.25)

Given points are:

P(₋2 , 2.5)

Q(1.4 , 4)

midpoint of PQ = ?

A location in the middle of a line connecting two points is referred to as the midpoint. The midpoint of a line is located between the two reference points, which are its endpoints. The line that connects these two places is split in half equally at the halfway.

The midpoint calculation is the same as averaging two numbers. As a result, by adding any two integers together and dividing by two, you may find the midpoint between them.

Midpoint formula (x,y) = (x₁ ₊ x₂/2 , y₁ ₊ y₂/2)

we have two points:

P(₋2,2.5) = (x₁,y₁)

Q(1.4,4) = (x₂,y₂)

Midpoint = (₋2 ₊ 1.4/2 , 2.5₊4/2)

= (₋0.6/2 , 6.5/2)

= (₋0.3 , 3.25)

Hence we determined the midpoint of PQ as (₋0.3 , 3.25)

Learn more about coordinate geometry here:

brainly.com/question/7243416

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2 years ago

Paula used these steps to solve an equation:

Lina20 [59]

D, between steps 4 and 5

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3 years ago

Answer this correctly for brainliest pls!!

Molodets [167]

A function that depicts depreciation can be represented as equations, graphs and tables.

<h3>The yearly value of each car for the first five years</h3>

The functions are given as:

$V(t) =C(1 - r^t)$

$V(t) =C(1 - r)^t$

Where:

C = 5895 --- the initial value of the car

r = 22% --- the rate of depreciation

For the first 5 years, the values of t = 1, 2, 3, 4 and 5

For the first function, we have:

$V(1) =5895(1 - 22\%^1) = 4598.1$

$V(2) =5895(1 - 22\%^2) = 5609.7$

$V(3) =5895(1 - 22\%^3) = 5832.2$

$V(4) =5895(1 - 22\%^4) = 5881.2$

$V(5) =5895(1 - 22\%^5) = 5892.0$

For the second function, we have

$V(1) =5895(1 - 22\%)^1 = 4598.1$

$V(2) =5895(1 - 22\%)^2 = 3586.5$

$V(3) =5895(1 - 22\%)^3 = 2797.5$

$V(4) =5895(1 - 22\%)^4 =2182.0$

$V(5) =5895(1 - 22\%)^5 = 1702.0$

So, the table of values is:

$\left[\begin{array}{ccc}Years&Car\ 1&Car\ 2\\1&4598.1&4598.1\\2&5609.7&3586.5\\3&5832.2&2797.5\\4&5881.2&2182.0\\5&5892.0&1702.0\end{array}\right]$

See attachment for the graphs of the two functions

<h3>Interpreting the graphs</h3>

The graph of car 1 increases up to C(t) = 5895, and then remains constant as the value of t increases while the graph of car 2 follows an exponential pattern.

This means that, the graph 2 that follows an exponential pattern is more realistic

<h3>The worth of the cars after 5 years</h3>

From the table, the worth of car 1 is $5892.0, while the worth of car 1 is $1702.0

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5 0

2 years ago