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Pavel [41]
3 years ago
15

What is the slope of the line in this graph?

Mathematics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

5/7

Step-by-step explanation:

B

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Solve for x.
Doss [256]

Answer:

x= 16

Step-by-step explanation:

First, you want to distribute each side! (you're gonna wanna learn this because you will be having to do it for the next 3 years no joke it sucks)

7(x+2) can be distributed as 7x+14 after multiplying 7 times x and 7 times 2, and 6(x+5) can be distributed as 6x+30.

Now, you have to get the x on one side to solve for x (so like x=__).

To do this, look at the equation as of now. 7x+14=6x+30.

We can minus 14 and bring that to the right, and minus 6x and bring that to the left to separate the x's and the regular numbers.

Now we have  16=x (or x=16).

5 0
3 years ago
The price of an item is reduced 70% the original price $90 what is the price now?
uranmaximum [27]
90 - (90 × .7) = $27

hope this helps
7 0
3 years ago
Read 2 more answers
Customers can pick their own apples at the Happy Apple Farm. They pay $5
kotegsom [21]

Answer: C

Step-by-step explanation:

For this problem, we know that customers already have to pay $5 just to enter the farm. The $5 is basically a flat fee. Our equation would be:

y=5+____

Now, we know that the apples cost $2.50 per pound. Our final equaiton would be:

y=5+2.5x

6 0
3 years ago
Complete the table using the equation y = 4x + 6.<br><br> x= -1, 0 1, 2, 3<br> y=
victus00 [196]
Plug in x for the y
8 0
3 years ago
A plane has an airspeed of 134 km divided by h. It is flying on a bearing of 78 degrees while there is a 21 km divided by h wind
ANEK [815]

Answer:

Ground speed = 131.25 km/h

Bearing = 92.68º

Step-by-step explanation:

If we imagine a triangle to depict the question with one side 134 km/h at an angle of 78º to the right of vertical (the plane's speed vector).

At the end, we have a line 21 km/h at an angle of 180 (from north), a vertical down from the end of the plane's vector. This vertex is angle B

This makes a triangle with the interior angle B of 78º.

The 3rd side is the ground speed which we can find using the Cosine rule:

b² = a² + c² - 2•a•c•cos(78)

b² = 134² + 21² - 2•134•21•cos(78)

b² = 17226.873

b = 131.25 km/h

The true course bearing" is the ground track. Thus;

Using the Sine rule to find angle A, we have;

(sin(A))/34= sin(78)/b

Thus,

sin(A) = (34 x sin(78))/131.25

sin(A) = 0.2534

A = sin^(-1)0.2534

A = 14.68º

Ground track = A + 78 = 14.68 + 78 = 92.68º

8 0
3 years ago
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