Answer:
<em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>
Step-by-step explanation:
<u>f</u><u>{</u><u>5</u><u>}</u> = <u>6</u><u>(</u><u>5</u><u>^</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>2</u><u>(</u><u>5</u><u>)</u><u> </u><u>-</u><u> </u><u>7</u>
g{-3}= 4(-3)-3
= <u>6</u><u>(</u><u>2</u><u>5</u><u>)</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>
-12 - 3
= <u>150</u><u> </u><u>+</u><u> </u><u>1</u><u>0</u><u> </u><u>-</u><u> </u><u>7</u>
- 15
= <u>1</u><u>5</u><u>3</u>
-15
= <u>-</u><u>5</u><u>1</u>
5
= <em><u>-</u></em><em><u>1</u></em><em><u>0</u></em><em><u>.</u></em><em><u>2</u></em>
Answer:
A. 
B. Perimeter = 190.6 yd
Step-by-step explanation:
A. Distance between P(10, 50) and R(80, 10):





(nearest tenth)
B. Distance around the park = Perimeter = PR + PQ + QR
PR = 80.6 yd
PQ = |50 - 10| = 40 yd
QR = |80 - 10| = 70 yd
Perimeter = 80.6 + 40 + 70
Perimeter = 190.6 yd
Answer:
1680
Step-by-step explanation:
Considering repeatition is not allowed.
We can use permutation to reach to the required answer.
Consider four digits to be placed in four boxes. Now for the number to be odd, unit digit must be odd. Therefore, unit digit can only be filled by 1, 3, 5,7, or 9. That is 5 ways. Now, other three boxes can be filled with 8, 7 and 6 ways respectively.
Therefore, Total numbers = 5×8×7×6 = 1680
O.6 easy because of the answer that is why
Let h(t) represent the height of the projectile after t seconds. If the projectile is being launched from the ground, then h(0)=0, and h(t)=-4.9t²+98t. When the equation is in this form, the maximum height is determined by -98/2(-4.9), or after 10 seconds. Thus
-4.9(100)+98(10)=490 m as the highest point of the projectile
Then, when it hits the ground, h(t)=0, so
0=-4.9t²+98t
98t=4.9t²
4.9t=98
t=20
☺☺☺☺