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3 years ago

-2.2 = x - 4.2 solve for x

Mathematics

1 answer:

Ann [662]3 years ago

4 0

Answer:

Step-by-step explanation:

Add 4.2 to both sides

x = 2

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in quadrilateral ABCD, AE=x+10, and BE=3x-18. for what value of x is ABCD a rectangle? a.24 b.14 c.18 d.16

Evgen [1.6K]

Answer:

for x = 14, the given ABCD is a RECTANGLE.

Step-by-step explanation:

Given : ABCD is a quadrilateral.

E is the intersection points of the diagonal AC and BD.

AE = x+10, and BE= 3x -18

Now, as we know:

IN A RECTANGLES , DIAGONALS BISECT EACH OTHER.

⇒ E is the mid point of AC and BD respectively.

⇒ AE = BE

⇒ x+10 = 3 x - 18

or, 10 + 18 = 3 x - x

or, 2 x = 28

or, x = 28/2 = 14 ⇒ x = 14

Hence, for x = 14, the given ABCD is a RECTANGLE.

4 0

3 years ago

How do you solve this

likoan [24]

The answer will be -316. Hope it help!

5 0

4 years ago

P is the midpoint of DE. the coordinates of D are (4,6) and the coordinates of P are (2,3). Find the coordinates of E.

Juli2301 [7.4K]

Answer:

(0,0), if you graph it then double the line you had it goes to 0,0

6 0

3 years ago

Read 2 more answers

(PLZZZZ HELP ME its actually easy I am trying to check my work) Bob's family of three was driving to Washington D.C.. They were

Anon25 [30]

Yes, they have enough money and

3 0

3 years ago

Americans spend an average of 4 hours per day online.If the standard deviation is 26 minutes, find the range in whitch at least

Mamont248 [21]

Answer:

The range in which at least 88.89% of the data will lie is (162,318).

Step-by-step explanation:

Given:

Average time spend online, $\bar x$ = $4$ hrs = $240$ mins

Standard deviation, $s$ = $26$ mins

We have to find the range in which at least 88.89% of the data will lie by using Chebyshev's theorem :

Formula :

Lower range = $\bar x-ks$

Higher range = $\bar x +ks$

Now we have to find k values.

We know that the percentage of the data that lies within 'k' standard deviation is at least,1-1/k^2 and k > 1.

⇒ $88.89\% = 0.8889$

⇒ $1-\frac{1}{k^2} = 0.8889$

⇒ $1-0.8889=\frac{1}{k^2}$

⇒ $0.1111=\frac{1}{k^2}$

⇒ $\frac{1}{0.1111} =k^2$

⇒ $\sqrt{\frac{1}{0.1111} } =k$

⇒ $3=k$

Plugging the value of k=3 in the formula above.

The range is $\bar x-ks,\bar x+ks$ .

⇒ $240-3(26), 240+3(26)$

⇒ $240-78,240+78$

⇒ $162,318$

So,

The range in which at least 88.89% of the data will lie is (162,318).

6 0

4 years ago