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3 years ago

Write the repeating decimal as a fraction

Mathematics

2 answers:

kenny6666 [7]3 years ago

4 0

Answer:

$\frac{41}{99}$

Step-by-step explanation:

We require 2 equations with the repeating digits placed after the decimal point.

let x = 0.4141.. → (1) Multiply both sides by 100

100x = 41.4141.. → (2)

Subtract (1) from (2) thus eliminating the repeating digits

99x = 41 ( divide both sides by 99 )

x = $\frac{41}{99}$

That is 0.4141.... = $\frac{41}{99}$

olga_2 [115]3 years ago

3 0

Answer:

The correct answer is: $\frac{37}{90}$

Step-by-step explanation:

You're using Acellus, right?

Let me guess: Algebra I?

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So we now have to find out how much more it will cost for a ski boat than a sail boat. All we do is subtract 352 by 292

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Step-by-step explanation:

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A consumer products company found that 42% of successful products also received favorable results from test market research, w

blagie [28]

Answer:

(1) The probability of a successful product given the product is favorable is 0.7778.

(2) The probability of a successful product given the product is unfavorable is 0.2391.

(3) The probability of a unsuccessful product given the product is favorable is 0.2222.

(4) The probability of a unsuccessful product given the product is favorable is 0.7609.

Step-by-step explanation:

Denote the events as follows:

S = a product is successful.

F = a product is favorable.

The information provided is:

$P(S\cap F)=0.42\\P(S\cap F^{c})=0.11\\P(S^{c}\cap F)=0.12\\P(S^{c}\cap F^{c})=0.35\\$

The law of total probability states that:

$P(A)=P(A\cap B)+P(A\cap B^{c})$

Use the law of total probability to compute the probability of a favorable product as follows:

$P(F)=P(S\cap F)+P(S^{c}\cap F)\\=0.42+0.12\\=0.54$

The probability of a favorable product is 0.54.

The conditional probability of an event A given that another event B has already occurred is:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

(1)

Compute the value of P (S|F) as follows:

$P(S|F)=\frac{P(S\cap F)}{P(F)}=\frac{0.42}{0.54}=0.7778$

Thus, the probability of a successful product given the product is favorable is 0.7778.

(2)

Compute the value of $P(S|F^{c})$ as follows:

$P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}=\frac{0.11}{(1-0.54)}=0.2391$

Thus, the probability of a successful product given the product is unfavorable is 0.2391.

(3)

Compute the value of $P (S^{c}|F)$ as follows:

$P (S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F)}=\frac{0.12}{0.54}=0.2222$

Thus, the probability of a unsuccessful product given the product is favorable is 0.2222.

(4)

Compute the value of $P (S^{c}|F^{c})$ as follows:

$P (S^{c}|F)=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}=\frac{0.35}{(1-0.54)}=0.7609$

Thus, the probability of a unsuccessful product given the product is favorable is 0.7609.

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Helga [31]

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