What is the domain of the function

m_a_m_a [10]

Answer:31/40

Step-by-step explanation:

To add you have to have a common denominator. To get that you can multiply each fraction by one in different ways. 2/5 *8/8= 16/40 and 3/8* 5/5= 15/40 and then add those two to give you 31/40.

5 0

3 years ago

Read 2 more answers

A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find

Veseljchak [2.6K]

Answer:

Approximately $68.5\; \rm mm$ .

Step-by-step explanation:

Convert the angle of this sector to radians:

$\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}$ .

The formula $s = r\, \theta$ relates the arc length $s$ of a sector of angle $\theta$ (in radians) to the radius $r$ of this sector.

In this question, it is given that the arc length of this sector is $s = 36\; \rm mm$ . It was found that $\theta = 2.22$ radians. Rearrange the equation $s = r\, \theta$ to find the radius $r$ of this sector:

$\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}$ .

The perimeter of this sector would be:

$\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}$ .

8 0

3 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

4 0

4 years ago

What percent of 4c in each expression? 0.2c

Ymorist [56]

The percentage of 4c in the expression 0.2c is 2000%

<h3>How to determine the percentage of 4c?</h3>

The expression is given as:

0.2c

The percentage of 4c is then calculated as:

4c/0.2c

Evaluate the quotient

20

Express as percentage

2000%

Hence, the percentage of 4c in 0.2c is 2000%