Find the volume between the cone X= sqrt(y^2 + z^2) and the sphere x^2 + y^2 + z^2 = 16.
1 answer:
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y=∣x−1∣={
1−x
x−1
x<1
x≥1
}
Similarly y=3−∣x∣={
3+x
3−x
x<0
x≥0
}
The required region is a rectangle with length 2
2
and breadth
2
.
Hence, the area is 4. Hence, all the options are correct
Answer:
(-3,8) and (4,-6)
Step-by-step explanation:
Segment DE with slope -2 is perpendicular to segment EF with slope 1/2. The triangle is a ...
C. right triangle
C. right triangle