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3 years ago

8

A pack of gum costs 75 cents. That is 3 cents less than three times what the pack cost 20 years ago. Which equation could be use

d to find the cost of the gum 20 years ago?

2 answers:

Tamiku [17]3 years ago

7 0

75-3×3x=?
I believe that would be the equation.

babunello [35]3 years ago

7 0

75-3x3x=_______ is your equation

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Solve for b:<br>10abc - 2d = 3d

gulaghasi [49]

Answer:

b = d/(2ac)

Step-by-step explanation:

10abc - 2d = 3d

Add 2d to each side

10abc - 2d+2d = 3d+2d

10 abc = 5d

Divide each side by 10ac

10 abc/ (10ac) = 5d/10ac

b = d/(2ac)

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3 years ago

URGENT! 40 POINTS! PLEASE HELP!

umka2103 [35]

Answer:

(a) $8 x(5 x-6)=40 x^{2}-48 x$

(c) $\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-21 x+18\end{aligned}$

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation $8 x(5 x-6)$

$8 x(5 x-6)=40 x^{2}-48 x$

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation $-4 x\left(2 x^{2}+1\right)$

$-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x$

Hence, the given statement is false.

(c) To find verify the answer we need to multiplying the equation $(x-3)(5 x-6)$

$\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}$

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation $(2 x+3)\left(x^{2}+3 x-5\right)$

$\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}$

Hence, the given statement is false.

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Cost:amount
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EastWind [94]

<span>x=y+2
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<span>x=y+2
</span><span>x=1+2
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answer
x = 3 and y = 1</span>

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Answer:

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Step-by-step explanation:

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