Answer: Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.
Step-by-step explanation:
Since we have given that
Let A be the event of getting a faulty switch.
Let B be the event of getting a defective cord.
Here, P(A∪B) = 4% = 0.04
P(A∩B) = 0.1% = 0.001
P(A) = 2.5% = 0.025
We need to find P(B):
As we know that

Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.
Answer: 4
Try just dividing 23/5 and you’d get 4 something. But since 5.97 is close to 6 you can also mentally divide 23/6 and get 3something (it’d be really close to 4)
(C)
Step-by-step explanation:
The volume of the conical pile is given by

Taking the derivative of V with respect to time, we get


Since r is always equal to h, we can set

so that our expression for dV/dt becomes


Solving for dh/dt, we get


