1. The weights of 30 students in a class ( in Kg ) are as follows. 42 , 52, 46 ,63, 47 ,40,50,63,52, 57,40,47,55 ,52, 49, 42,56,
enyata [817]
Step-by-step explanation:
I think when you put the numbers orderwise
The range 40 - 50 in which most students lie
Given:
z = (x - μ)/σ = z value
x = independent variable = 11
μ = mean = 8
σ = standard deviation = 3
Solution:
X ~ N (8, 3)
For day 1, n = 5
P (X < = 11) = P (Z < = 11 – 8 / 3/Sqrt5) = P (Z <
=2.23) = 0.987126
For day 1, n = 6
P (X < = 11) = P (Z < = 11 – 8 / 3/sqrt6) = P (Z <
=2.45) = 0.992857
For both days:
P (X <= 11) = P (X <= 11) = (0.987126) (0.992857) =
0.9801
Given:
To find:
The value of b and SR.
Solution:
We have,
(Given)
(CPCTC)
Substituting the given values, we get
Divide both sides by -4.
Now,
Therefore, the value of b is 5 and the measure of SR is 43 units.
Answer:
for the first one 7.66 but i might be wrong so sorry if i got it wrong
Step-by-step explanation:
0.16 per mile so 7.5 + 0.16 = 7.66
