8) v=1/3 x 6^2 x 11
= 132cm^3
10) 80ft^3
11) 72km^3
Hope this helps!!
To simplify the problem it would be: -18xy+18y^2
Im guessing it would be about 50 degrees
The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
Read more about transformation at:
brainly.com/question/4289712
#SPJ1
Answer: -1
Step-by-step explanation: So if the Temperature last night was at -3o C and now it is -4o C it went down by 1 but dont forget the negative symbol.-1
you can think like this: -3-4=-1
