Answer: HERE IS THE GRAPH AND PLS CORRECT ME IF I"M WRONG :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
Answer:
First, we can write:
x
=
3
.
¯¯¯¯
24
Next, we can multiply each side by
100
giving:
100
x
=
324
.
¯¯¯¯
24
Then we can subtract each side of the first equation from each side of the second equation giving:
100
x
−
x
=
324
.
¯¯¯¯
24
−
3
.
¯¯¯¯
24
We can now solve for
x
as follows:
100
x
−
1
x
=
(
324
+
0
.
¯¯¯¯
24
)
−
(
3
+
0
.
¯¯¯¯
24
)
(
100
−
1
)
x
=
324
+
0
.
¯¯¯¯
24
−
3
−
0
.
¯¯¯¯
24
99
x
=
(
324
−
3
)
+
(
0
.
¯¯¯¯
24
−
0
.
¯¯¯¯
24
)
99
x
=
321
+
0
99
x
=
321
99
x
99
=
321
99
99
x
99
=
3
×
107
3
×
33
x
=
3
×
107
3
×
33
x
=
107
33
Now, we can convert this improper fraction to a mixed number:
x
=
107
33
=
99
+
8
33
=
99
33
+
8
33
=
3
+
8
33
=
3
8
33
3
.
¯¯¯¯
24
=
3
8
33
Answer:
(f + g)(x) = 7x - 1
Step-by-step explanation:
Given : f(x) = 5x – 2 and g(x) = 2x + 1
We have to find (f + g)(x)
Consider (f + g)(x) = f(x) + g(x)
Also, given f(x) = 5x – 2 and g(x) = 2x + 1
Substitute, we have,
f(x) + g(x) = 5x - 2 + 2x + 1
Like Terms are terms having same variable with same degree.
Simplify by adding like terms, we have,
f(x) + g(x) = 5x + 2x - 2 + 1
f(x) + g(x) = 7x - 1
Thus, (f + g)(x) = 7x - 1
a=9/14
b=32/8
c=25/13
That is the answer for these questions.
