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Svetlanka [38]
3 years ago
5

(HELP THIS IS TIMED!)

Mathematics
2 answers:
scoundrel [369]3 years ago
6 0

Answer:

1,3,5,6

Step-by-step explanation:

Sorry I didn't get to this in time, but if you see this, please give me brainliest, apariently I need it to get to the next answer. Thank you for your time.

nevsk [136]3 years ago
5 0

Answer:

8x^2 with 40 as the numerator

Step-by-step explanation:

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7)
saul85 [17]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q
RoseWind [281]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\

Let F is a value of the content so, the value is:

\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\

Now, we calculate the tooling value:

\to p[\frac{C}{F}]

using the baues therom:

\to p[\frac{C}{F}] =  \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }  

            =  \frac{ 0.17  \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14  } \\\\=  \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\=  \frac{0.0238}{0.1399} \\\\=0.1701

7 0
3 years ago
Need help ASAP! Looking for someone to show work, it’s completely fine if you don’t tho!
andreyandreev [35.5K]
D since (-5 x -5) = 25 and (7 x -8) = -56. Add 25 and -56 and your answer is D. -31
5 0
3 years ago
Answer both questions if u cant see all the answers it don't matter all u need is the question
babymother [125]
First one is 7.73 (23.19/3)
Second one is 14.04 ((19.71/7.3) x 5.2)
6 0
3 years ago
Read 2 more answers
Need help on this question
stellarik [79]

Answer:nhjhbghhnkjn hojn

3 0
3 years ago
Read 2 more answers
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