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Answer:
1i) nth term = 12(-b/4)^(n-1)
ii) nth term = 3(-1/9)^(n-1)
2i) Sixth term= (-3b^5)/256
ii) Eight term = -1/1594323
Question:
The complete question as found on brainly (question-10746111):
Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.
i) 12,-3b,......sixth term
ii) 3,-1/3,..........;8th term?
Step-by-step explanation:
1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.
i) 12,-3b,......;sixth term
1st term = a= 12
r = common ratio = 2nd term /1st term
r = -3b/12 = -b/4
Then we would find the nth term
See attachment for details
ii) 3,-1/3,..........;8th term
1st term = a= 3
r = common ratio = 2nd term /1st term
r = (-⅓)/3 = (-⅓)(⅓) = -1/9
Then we would find the nth term
See attachment for details
2) we are to determine the sixth term in (i) and eight term in (ii)
See attachment for details
Sixth term= (-3b^5)/256
Eight term = -1/1594323
Answer:
Step-by-step explanation:
- First we find the slope of the line AB passing through the point (2,0)
- line AB is perpendicular to the line
, this equation is slope intercept for, which is
so our m or slope is
- Since the slope of line AB is perpendicular to
then we use the equation
, so what do we multiply
by to get -1? -4 right, so that's the slope of line AB with the point (2,0)
- Now line CD is parallel to line AB, that means it has the same slope as AB, so slope of CD is -4
- So we make the equation
so m= -4 and our point is (-1,6)
thats the equation of line side CD