One way would be to find the distance from the point to the center of the circle and compare it to the radius
for

the center is (h,k) and the radius is r
and the distance formula is
distance between

and

is

r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so



the radius is

center is (-2,3)
find distance between (8,4) and (-2,3)






≈4.2

≈10.04
do r<D
(8,4) is outside the circle
If you look at the picture, you set it up as part over whole is equal to percent over 100. then you just multiply across.
Answer:
-36
Step-by-step explanation:
Express it in an equation:
6+(x/9)=2
-6 -6
x/9=-4
-36
Answer:
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher
Step-by-step explanation:
Data provided in the question:
sample size, n = 103
Mean temperature, μ = 98.3
°
Standard deviation, σ = 0.73
Degrees of freedom, df = n - 1 = 102
Now,
For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]
Therefore,
CI = 
Thus,
Lower limit of CI = 
or
Lower limit of CI = 
or
Lower limit of CI = 98.11
and,
Upper limit of CI = 
or
Upper limit of CI = 
or
Upper limit of CI = 98.49
Hence,
CI = (98.11 , 98.49)
The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F
J is not a function.
for y to be a function of x, it needs to have every input x value mapping to one, and only 1, output y value.
we see that for graph J, x = -3 maps to both -3 and -2.
can't be a function