The answer is out of every 5 trials, the desired out come will be approximately 2 times.
Answer:
Step-by-step explanation:
![S_{31} = 9 \cdot 31 + [-0.5 \cdot \frac{31(31-1)}{2}] = 46.5](https://tex.z-dn.net/?f=S_%7B31%7D%20%3D%209%20%5Ccdot%2031%20%2B%20%5B-0.5%20%5Ccdot%20%5Cfrac%7B31%2831-1%29%7D%7B2%7D%5D%20%3D%2046.5)
![S_{40} = 40 + [-3 \cdot \frac{40(40-1)}{2}] = -2300](https://tex.z-dn.net/?f=S_%7B40%7D%20%3D%2040%20%2B%20%5B-3%20%5Ccdot%20%5Cfrac%7B40%2840-1%29%7D%7B2%7D%5D%20%3D%20-2300)
Answer:
as below
Step-by-step explanation:
to find the height of the pole recall the relationship of sin cos and tan to the triangle with this helpful mnemonic SOH CAH TOA
Sin = Opp / Hyp
Cos = Adj / Hyp
Tan = Opp / Adj
we will need to solve two triangles and subtract them.
one is the 15° one of the slope of the road and the other is the 57° one that is the angle of the sun. sooooo,
lets solve the 15° one first. We are told that the adj side is 75'
since we know the angle and the adj side and we want to find the Opp side let's use Tan b/c it has all of those in it :)
Tan(15) = Opp / 75
75*Tan(15) = Opp ( I'll put my calculator to work for this )
20.096 = Opp
that's the height of the road to the bottom of the flag pole along that flag pole axis into the ground
next lets solve the 57° triangle in the exact same way
Tan(57) =Opp / 75
75*Tan(57) = Opp
115.4898 = Opp
the tall triangle is the one that goes all the way into the ground, the small one is the one that is under the ground
so subtract the small one from the big one to find the height of the flag pole above the ground
115.4898-20.096 = 95.3938
so the flag pole is about 95.4 feet tall
:o that's pretty tall :
<u>Answer-</u>
<u>Solution-</u>
Given the two polynomials are 
So their product will be,
Distributing the Parentheses,
Applying minus-plus rules,
Simplifying further,
