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laila [671]
2 years ago
7

What is the highest degree in x³ - x²y² - y² + 2​

Mathematics
1 answer:
kobusy [5.1K]2 years ago
3 0

Answer:

X^3 is highest because of its exponet it’s higher than the rest

Step-by-step explanation:

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Find the area of the rhombus. d1 = 14 m; d2 = 18 m The area of the rhombus is ? m2.
xxTIMURxx [149]

<u><em>Answer:</em></u>

Area of rhombus = 126 m²

<u><em>Explanation:</em></u>

<u>We are given that the two diagonals of the rhombus are:</u>

D₁ = 14 meters and D₂ = 18 meters

<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>

Area = \frac{D_1 * D_2}{2}

<u>Substitute with the given values to get the area as follows:</u>

Area = \frac{14*18}{2}=126 m^2

Hope this helps :)

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2 years ago
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tiny-mole [99]

Answer:

Tasha is wrong because she can do more than six bags so she is wrong. Since she has a lot of stuff so she can more than six bags

Step-by-step explanation:

7 0
3 years ago
28 divided by negative 7
monitta
28 divded by -7 is -4
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3 years ago
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Please help me with this<br> Evaluate: 2^-4 =
givi [52]

Answer:  \frac{1}{16}

Step-by-step explanation:

Whenever an exponent is negative, you flip the solution.

For this, 2^4 = 2*2*2*2 = 4*4 = 16, however the exponent is negative, so flip 16 to get your final answer of \frac{1}{16}

5 0
2 years ago
The diameter of a circle has length 12. The center is at*(-5, 2). Give the equation
labwork [276]

Answer:

Equation of the circle is : x^{2} + 10x + y^{2} -4y -7 =0

Step-by-step explanation:

Let us consider the image attached in the answer area.

The center<em> O</em> has the co-ordinates i.e. <em>(-5,2)</em> and the diameter given is <em>12 units</em>.

We know that radius is half of diameter.

\text{Radius = }\dfrac{\text{Diameter}}{2}

\text{Radius = }\dfrac{12}{2}\\\Rightarrow \text{Radius = 6units}

The equation for circle given the center and radius, can be represented as:

(x-a)^{2}+ (y-b)^{2} = r^{2}

Where <em>(a,b)</em> is the co-ordinate of center and <em>r</em> is the radius.

Let us consider the following formula:

(p+q)^2 = p^{2}+ q^{2} +2pq\\(p-q)^2 = p^{2}+ q^{2} -2pq

(x-(-5))^{2}+ (y-2)^{2} = 6^{2}\\\Rightarrow (x+5)^{2}+ (y-2)^{2} = 36\\\Rightarrow x^{2} + 25 + 10x +y^{2} + 4-4y=36\\\Rightarrow x^{2} + 10x +y^{2} -4y-7=0

Hence, Equation of the circle is : x^{2} + 10x + y^{2} -4y -7 =0

4 0
2 years ago
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