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2 years ago

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Two mosquitos are sitting on the same ceiling fan. The radius of the ceiling fan is 16 inches. One mosquito is seated on the ver

y edge of the fan's blade, and one is seated 12 inches away from the center of the fan. The fan makes one revolution per second. How much farther, in inches, does the mosquito on the edge of the ceiling fan travel than the other mosquito in one second?
A 4π inches
B 8 inches
с 8π inches
D 112π inches

1 answer:

ivolga24 [154]2 years ago

6 0

Answer:

b

Step-by-step explanation:

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Answer:

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Nick decided to take 2/5 of the money in his bank account and donate it to a local charity. If nick donated $70 to a local chari

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Answer:

<u> The total amount = $175</u>

Step-by-step explanation:

Let the total amount in his bank account = x

Nick decided to take 2/5 of the money in his bank account and donate it to a local charity

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If nick donated $70 to a local charity

so, $\frac{2}{5} x = 70$

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∴ x = 5*70/2 = 350/2 = $175

<u>So, The total amount = $175</u>

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At what point on the curve x^2 + y^2 = 9 is the tangent line vertical?

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Tamara has a cell phone plan that charges $0.07

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Problem 4: Solve the initial value problem

pishuonlain [190]

Separate the variables:

$y' = \dfrac{dy}{dx} = (y+1)(y-2) \implies \dfrac1{(y+1)(y-2)} \, dy = dx$

Separate the left side into partial fractions. We want coefficients a and b such that

$\dfrac1{(y+1)(y-2)} = \dfrac a{y+1} + \dfrac b{y-2}$

$\implies \dfrac1{(y+1)(y-2)} = \dfrac{a(y-2)+b(y+1)}{(y+1)(y-2)}$

$\implies 1 = a(y-2)+b(y+1)$

$\implies 1 = (a+b)y - 2a+b$

$\implies \begin{cases}a+b=0\\-2a+b=1\end{cases} \implies a = -\dfrac13 \text{ and } b = \dfrac13$

So we have

$\dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = dx$

Integrating both sides yields

$\displaystyle \int \dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = \int dx$

$\dfrac13 \left(\ln|y-2| - \ln|y+1|\right) = x + C$

$\dfrac13 \ln\left|\dfrac{y-2}{y+1}\right| = x + C$

$\ln\left|\dfrac{y-2}{y+1}\right| = 3x + C$

$\dfrac{y-2}{y+1} = e^{3x + C}$

$\dfrac{y-2}{y+1} = Ce^{3x}$

With the initial condition y(0) = 1, we find

$\dfrac{1-2}{1+1} = Ce^{0} \implies C = -\dfrac12$

so that the particular solution is

$\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}$

It's not too hard to solve explicitly for y; notice that

$\dfrac{y-2}{y+1} = \dfrac{(y+1)-3}{y+1} = 1-\dfrac3{y+1}$

Then

$1 - \dfrac3{y+1} = -\dfrac12 e^{3x}$

$\dfrac3{y+1} = 1 + \dfrac12 e^{3x}$

$\dfrac{y+1}3 = \dfrac1{1+\frac12 e^{3x}} = \dfrac2{2+e^{3x}}$

$y+1 = \dfrac6{2+e^{3x}}$

$y = \dfrac6{2+e^{3x}} - 1$

$\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}$

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1 year ago