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nekit [7.7K]
3 years ago
11

A cone has a diameter labeled twelve centimeters and a height labeled thirty-two centimeters. Find the area of a vertical cross

section through the center of the base of the cone.
Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

A=0.0192

Step-by-step explanation:

Diameter labeled twelve centimetres D =12cm => 0.12

height labeled thirty-two centimetres H= 32cm => 0.32

Generally the vertical cross section of this cone is a triangle

Mathematically solving

Area of vertical cross section through the center of the base of the cone is given by A=1/2 D*height

A=R*H

Therefore

A=\frac{0.12}{2} *0.32

A=0.06 *0.32

A=0.0192

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What is the expression for "the difference between 5 times a number and twice that number"?
ycow [4]
Hey there :)

Before translating the sentence into mathematics, let r represent 'a number'

5 times a number = 5r
2 times that number = 2r

The difference between them = 5r - 2r 

* Your equation 
5r - 2r

* Solving the equation 
= 5r - 2r
= 3r
3 0
3 years ago
If LM=41-2x and NP=7x+5, find LM
Tatiana [17]
Answer:
LM = 33 units

Explanation:
From the drawing:
LM = NP
41 - 2x = 7x + 5
41 - 5 = 7x + 2x
36 = 9x
x = 9

This means that:
LM = 41 - 2x 
LM = 41 - 2(4) 
LM = 33 units

Hope this helps :)

8 0
3 years ago
Subtract. 1 1/3−6 Enter your answer as a simplified mixed number by filling in the boxes IF YOU GET THIS RIGHT ILL GIVE BRAINLES
Vesnalui [34]

Answer:

-4\frac{2}{3}

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the value of X
sashaice [31]

Answer:

x = 7

Step-by-step explanation:

=> 9/72 = 3x-20/56

=> 9×45/72 = 3x-20

=> 27/3 = x

=> x = 7

3 0
2 years ago
Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm
Vlad1618 [11]

Answer:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

The distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar x =512 represent the sample mean

\sigma=100 represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}   (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}

And we can find the critical value z_{\alpha/2} like this:

z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576

And we know that on the right tail of the z score =2.576 we have \alpha/2 of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998=\alpha/2, so then \alpha=0.00498*2=0.009995 \approx 0.01, and then we can find the confidence like this:

Confidence =1-\alpha=1-0.01=0.99

And then the confidence level would be given by 99%

8 0
3 years ago
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