<span>y-intercept: set x=0 </span>
<span>y = 3(0)^2 - 6(0) - 8 </span>
<span>y = -8 </span>
<span>x-intercept: set y=0 </span>
<span>0 = 3x^2 - 6x - 8</span>
Answer:
Step-by-step explanation:
He will actually need to wait for 12 weeks. And that is because if you look at the multiples of 6 and 4 and you'll notice that 12 is the lowest common multiple between them. So you start counting from 6 and 4 at the same time until you notice the LCM of these two numbers then on which ever you number you settle on is how long he will need to wait.
52.5 Yards (yd).
7 + 7 = 14
14 + 14 = 28 ( 10 + 10 + 4 + 4)
14 + 28 = 42 (4 - 2 + 8 = 10 + 20 + 10)
42 + 10.5 = 52.5
⚠⚠ if you need to multiply this by itself (squaring is the proper name) then the answer is 2756.25 Yards.
Answer:
2. a and b only.
Step-by-step explanation:
We can check all of the given conditions to see which is true and which false.
a. f(c)=0 for some c in (-2,2).
According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.
b. the graph of f(-x)+x crosses the x-axis on (-2,2)
Let's test this condition, we will substitute x for the given values on the interval so we get:
f(-(-2))+(-2)
f(2)-2
-1-1=-3 lower limit
f(-2)+2
1+2=3 higher limit
according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.
c. f(c)<1 for all c in (-2,2)
even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.
The final answer is then 2. a and b only.
