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Degger [83]
2 years ago
10

Solve for x. I’ll give points!

Mathematics
2 answers:
Licemer1 [7]2 years ago
4 0

→x + 9 = 2(2x - 3)

→x + 9 = 4x - 6

→ 4x - x = 9 +6

→ 3x = 15

→ x = 5

jeka57 [31]2 years ago
3 0

Answer:

  • x = 5

  <u>explanation</u>:

solving similarities:

bigger triangle is double of the smaller triangle.

<u>balancing them</u>:

→ x + 9 = 2(2x - 3)

→ x + 9 = 4x - 6

→ 4x - x = 9 + 6

→ 3x = 15

→ x = 5

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$3.30 because taking the cost of 24, which is $7.20, and dividing is by the amount, 24, you get that one Blow-Pop costs $0.30. Then to find how many 11 costs you just need to multiply $0.30 by 11, and you get $3.30.

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What is 20 plus14 plus 9plus -11plus-4
Evgesh-ka [11]

Answer:

20+14+9+-11+-4=20

Step-by-step explanation:

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Describe the main parts of a proof? ..
sattari [20]

Answer:

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3 years ago
George is considering two different investment options. The first offers 7.4% per year simple interest on the initial deposit. T
pentagon [3]

Answer:

Part A) \$12,220.00

Part B) \$12,134.08

Part C) The simple interest investment is better than the compounded  interest investment at the end of three years.

Part D)  see the explanation

Step-by-step explanation:

Part A) Determine the value of the simple-interest investment at the end of three years

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=3\ years\\ P=\$10,000\\r=7.4\%=7.4/100=0.074

substitute in the formula above

A=10,000(1+0.074*3)

A=10,000(1.222)

A=\$12,220.00

Part B) Determine the value of the compound-interest investment at the end of three years

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=3\ years\\ P=\$10,000\\r=6.5\%=6.5/100=0.065\\n=4

substitute in the formula above

A=10,000(1+\frac{0.065}{4})^{4*3}  

A=10,000(1.01625)^{12}  

A=\$12,134.08

Part C) Which investment is better over the first three years?

Compare the two investment

\$12,134.08 < \$12,220.00

The compounded  interest investment is less than the simple interest investment

therefore

The simple interest investment is better than the compounded  interest investment at the end of three years

Part D) How would you advise George to invest his money if he is unsure how long he’ll keep the money in the account?

we have

A=10,000(1+0.074t)  ----> simple interest formula as a function of the time t

A=10,000(1.01625)^{4t}   ----> compound interest formula as function of the time t

Look to the attached graph below

The red line represents the simple interest investment

The blue curve represents the compounded interest investment

After 0 years and before 4.179 years the red line is over the blue curve, that means the simple interest is better because it gives more money than the compounded interest

After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest

therefore

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

4 0
3 years ago
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Lerok [7]

Answer: x= 2, y= -1/2

Step-by-step explanation:

5 0
3 years ago
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