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solniwko [45]
3 years ago
11

Danielle says the answer is "A". Is she correct? If she is,why? And if she isn't,what is the correct answer?​

Mathematics
1 answer:
Naddik [55]3 years ago
3 0

Answer:

She is incorrect. The correct answer is 285.74

Step-by-step explanation:

A= (pi)r^2

Training wheel: A= (3.14)(3)^2=28.26in^2

Wheel: A= (3.14)(10)^2= 314in^2

314-28.26=285.74in^2

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Help please, I'm stuck on this :/
nlexa [21]

Do you have a calculator? you can solve it by substituting x.

y=16x^2

0: y = 16(0)^2 = 16(0) = 0

(x = 0 , y = 0)

0.5: y = 16(0.5)^2 = 16(0.25) = 4

(x = 0.5 , y = 4)

1: y = 16(1)^2 = 16(1) = 16

(x = 1 , y = 16)

1.5: y = 16(1.5)^2 = 16(2.25) = 36

(x = 1.5 , y = 36)

2: y = 16(2)^2 = 16(4) = 64

(x = 2 , y = 64)

2.5: y = 16(2.5)^2 = 16(6.25) = 100

(x = 2.5 , y = 100)

3 : y = 16(3)^2 = 16(9) = 144

(x = 3 , y = 144)

4: y = 16(4)^2 = 16(16) = 256

(x = 4 , y = 256)

if you multiply a negative number by itself, it will become positive. So, -4, -3, -2.5, -2, -1.5, -1, -0.5 will be the same as the positive 4, 3, 2.5, 2, 1.5, 1, 0.5.

I'm not sure about the pattern, but if you graph it, it'll be symmetrical across the y-axis.

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3 years ago
Park rangers asked visitors to keep track of which animals they saw while hiking. After two weeks, the rangers added together al
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D because it is the most resionobal
6 0
3 years ago
Read 2 more answers
What is the value of x?
Ray Of Light [21]
The Pythagorean Theorem states that a^2+b^2=c^2
We already have:
A^2+6^2=117
All we need to do is find the missing A by subtract b from c.
117-36=81
Now the square root of 81, 9.
So, x is 9 cm.
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3 years ago
Ms. Kork sold her car for $8700. This was $100 more than two fifths of what she had paid for the car originally. How much mad Ms
Ne4ueva [31]

Answer:

8600 is 100 less

3440?

Step-by-step explanation:

3 0
2 years ago
yesterday Stephanie spent $38.72 on new shoes and $23.19 on computer software when she was finished she had $38.18 how much mone
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Answer: She had $61.91,


Step-by-step explanation:


6 0
3 years ago
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