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sveta [45]
4 years ago
12

Jose has 4 friends and 3 apples how much would each friend get if he shared

Mathematics
2 answers:
blsea [12.9K]4 years ago
5 0

\bf \cfrac{\stackrel{\textit{total amount of apples}}{3}}{\stackrel{\textit{total amount of people}}{4}}\qquad \qquad \quad\stackrel{Jose}{ \cfrac{3}{4}}+\stackrel{friend}{\cfrac{3}{4}}+\stackrel{friend}{\cfrac{3}{4}}+\stackrel{friend}{\cfrac{3}{4}}=\cfrac{12}{4}=3

Anton [14]4 years ago
3 0
Everyone will get 3/4 of an apple
3/4 equals 0.75
Hope it helped
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If y varies directly with x and y=100 when x=5, what is the value of k?
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When it says varies directly, it means that y and x are going to be on opposite sides of the equals sign and that there is a constant, k,

y=kx

Plug in (5,100)

100=k(5)

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HELP
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
A forester studying diameter growth of red pine believes that the mean diameter growth will be different from the known mean gro
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Answer:

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

Step-by-step explanation:

Data given and notation  

\bar X=1.6 represent the sample mean

s=0.46 represent the sample deviation

n=32 sample size  

\mu_o =1.35 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:  

Null hypothesis:\mu =1.35  

Alternative hypothesis:\mu \neq 1.35  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

P-value  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

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3 years ago
Line l is parallel to line e in the figure below.
yulyashka [42]
After the 2 angles the third and fifth line are great
3 0
3 years ago
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