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oksano4ka [1.4K]
4 years ago
8

Solve algebraically for x: 3600 + 1.02x < 2000 + 1.04x

Mathematics
1 answer:
Nata [24]4 years ago
4 0

Answer:

x < 80000

Step-by-step explanation:

3600 + 1.02x < 2000 + 1.04x \\  \frac{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - 1.04x <  \:  \:  \:  \:    \:  \:  \:  \:  \:  \:  \:  \:  \:  - 1.04x}{3600 - 0.02x < 2000}  \\  \\ 3600 - 0.02x < 2000 \\  \frac{ - 3600 \:  \:  \:  \:  \:  \:  \:  \:  \:  <  - 3600}{ - 0.02x <  - 1600}  \\  \\  \frac{ - 0.02x}{ - 0.02}   <  \frac{ - 1600}{ - 0.02}  \\  \\ x < 80000

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