Solve algebraically for x: 3600 + 1.02x < 2000 + 1.04x

Mathematics

1 answer:

Nata [24]3 years ago

4 0

Answer:

$x < 80000$

Step-by-step explanation:

$3600 + 1.02x < 2000 + 1.04x \\ \frac{ \: \: \: \: \: \: \: \: \: \: \: \: - 1.04x < \: \: \: \: \: \: \: \: \: \: \: \: \: - 1.04x}{3600 - 0.02x < 2000} \\ \\ 3600 - 0.02x < 2000 \\ \frac{ - 3600 \: \: \: \: \: \: \: \: \: < - 3600}{ - 0.02x < - 1600} \\ \\ \frac{ - 0.02x}{ - 0.02} < \frac{ - 1600}{ - 0.02} \\ \\ x < 80000$

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<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

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