Question

If the resistance of one component of a series circuit is 3+j5  ohms, and the resistance of the second component of the circuit is 5−j8  ohms, and the resistance of the third component of the circuit is 6+j4  ohms, what is the total resistance in the circuit?

Answer 1

In a series circuit, the total resistance is obtained by R1+R2+R3+Rn where R is the resistance of each component

We have
R1 = 3+j5
R2 = 5-J8
R3 = 6+J4

Hence the total resistance, RT, is given

RT = 3 +j5 +5 - j8 + 6 +j4 = 14+j1