If the resistance of one component of a series circuit is 3+j5 ohms, and the resistance of the second component of the circuit
is 5−j8 ohms, and the resistance of the third component of the circuit is 6+j4 ohms, what is the total resistance in the circuit?
1 answer:
In a series circuit, the total resistance is obtained by R1+R2+R3+Rn where R is the resistance of each component
We have
R1 = 3+j5
R2 = 5-J8
R3 = 6+J4
Hence the total resistance, RT, is given
RT = 3 +j5 +5 - j8 + 6 +j4 = 14+j1
You might be interested in
Answer:
x = 11
Step-by-step explanation:
3/(3(2x-3)) = 2/(3x+5)
3(2x-3) = 6x - 9
3/(6x-9) = 2/(3x+5)
3(3x+5) = 2(6x-9)
9x + 15 = 12x - 18
12x - 9x = 15 + 18
3x = 33
x = 11
Answer:
rate of the boat in still water: 81 km/h
rate of the current: 18 km/h
Step-by-step explanation:
21/24
Divide 21 by 3. You get 7.
Divide 24 by 3. You get 8.
7/8 is your answer
Answer:
it has 3 steps
Step-by-step explanation:
The answer is to be 9.135