Answer:
OMG!!!! WHAT WERE YOU TRYING TO MAKE
Answer:
C(5,-9) and r=8.
Step-by-step explanation:
C(p, q) - center
r=radius
k:x^2 +y^2 +dx+ey+f=0
x^2+y^2 - 10x+18y+42=0
d=-10, e=18, f=42
p=-d/2=-(-10)/2=10/2=5
q=-e/2=-18/2=-9
r^2 =p^2+q^2-f
r^2 =5^2 +(-9)^2 - 42
r^2=25+81-42
r^2 =106-42
r^2 =64
r=sqrt(64)
r=8
C(p,q)=C(5,-9) r=8
Your numbers are 11 and 32
We know that:
a + b = 44
and
a = 3b
If we substitute “3b” in for a in the first equation, we get a numerical value for b
3b + b = 44
4b = 44
b = 11
Then we substitute the numerical value of b to solve for a:
a = 3b
a = 3(11) = 33
Let "a" and "b" be the two numbers
So a*b=-8 and a+b=-7
Therefore S=-7 and P=-8
Using (x^2)-S+P=0 => (x^2)-(-7)+(-8)=0 => (x^2)+7-8=0
By factorizing we get (x+8)(x-1)=0
So a can be either -8 or 1 and b can be 1 or -8
Meaning that the two numbers are -8 and 1.
