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3 years ago

Easy question 4 someone

Mathematics

2 answers:

neonofarm [45]3 years ago

8 0

Answer is (c) BC.

Angle A is only opposite to the side BC

olga_2 [115]3 years ago

8 0

Answer:

C. BC

Step-by-step explanation:

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A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. Write an equation to represent the car travels in miles and minu

Korvikt [17]

Answer:

d = 0.666t , where d is in miles and t is in minutes.

d = 39.94h, where d is in miles and h is in hours.

Step-by-step explanation:

A car travels $2\frac{1}{3} = 2.33$ miles in $3\frac{1}{2} = 3.5$ minutes at a constant speed.

Let the relation between the distance (d) traveled by car in miles after traveling t minutes is d = kt ......... (1)

Now, putting d = 2.33 miles and t = 3.5 minutes in the above equation we get,

2.33 = 3.5k

⇒ k = 0.666 (Approx.)

So, the equation (1) becomes d = 0.666t. (Answer)

Let us assume that the relation between the distance (D) traveled by car in miles after traveling h hours is d = Kh ............ (2)

Now, putting D = 2.33 miles and T = 3.5/60 = 0.058 hours in the above equation, we get

2.33 = 0.058K

⇒ K = 39.94

So, the equation (2) we get, d = 39.94h (Answer)

3 0

3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$