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musickatia [10]
3 years ago
6

Easy question 4 someone

Mathematics
2 answers:
neonofarm [45]3 years ago
8 0

Answer is (c) BC.

Angle A is only opposite to the side BC

olga_2 [115]3 years ago
8 0

Answer:

C. BC

Step-by-step explanation:

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When 9 is multiplied by a number less than eleven, add 1 to the tens place and subtract 1 from the ones place.
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Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 99​% confidenc
quester [9]

Answer: 18

Step-by-step explanation:

The formula to find the minimum sample size is given by :_

n=(\dfrac{z^*\cdot \sigma}{E})^2

, where \sigma = population standard deviation.

z*= critical z-value.

E= Margin of error.

Given : \sigma= 13

E= ± 8

We know that critical value corresponding to 99% confidence level = z*=2.576  [Using z-table]

Then, the required sample size would be :

n=(\dfrac{(2.576)\cdot (13)}{8})^2

\Rightarrow\ n=(4.186)^2

\Rightarrow\ n=17.522596\approx18 [Round to next integer.]

Hence, the required minimum sample size = 18

4 0
3 years ago
Write the value of 8 in 8091
Andrew [12]
The value of 8 is 8000
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3 years ago
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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
Which of the following represents the area of a rectangle with a length of (3x + 2)
Misha Larkins [42]

Answer:

WANNA HEAR SOME METAL

Step-by-step explanation:

WANNA HEAR ME ROAAAAAAAAAAAAAAAAAR

6 0
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