Answer:
T = ±22
Step-by-step explanation:
Let's solve your equation step-by-step.
0=−16t2+7744
Step 1: Add 16t^2 to both sides.
0+16t2=−16t2+7744+16t2
16t2=7744
Step 2: Divide both sides by 16.
16t2
16
=
7744
16
t2=484
Step 3: Take square root.
t=±√484
t=22 or t=−22
Answer:
The answer to your question is:
x = 1
y = 1
z = 0
Step-by-step explanation:
-2x + 2y + 3z = 0 (1)
-2x - y + z = -3 (2)
2x + 3y + 3z = 5 (3)
Solve (1) and (2)
Multiply 2 by 2
-2x + 2y + 3z = 0
-4x -2y + 2z = -6
-6x + 5 z = -6 (4)
Solve (2) and (3)
Multiply 2 by 3
-6x - 3y + 3z = -9
2x + 3y + 3z = 5
-4x + 6z = -4 (5)
Solve (4) and (5)
Multiply (4) by 2 and (5) by -3
-12x + 10 z = -12
12x - 18z = 12
-6z = 0
z = 0
Then
-4x + 6(0) = -4
-4x = -4
x = -4/-4
x = 1
Finally
-2(1) - y + (0) = -3
-2 - y = -3
-y = -3 + 2
y = 1
Answer:
idk
Step-by-step explanation:
how about you do the math yourself
Answer:
II. The sum of the residuals is always 0.
Step-by-step explanation:
A least squares regression line is a standard technique in regression analysis used to make the vertical distance obtained from the data points running to the regression line to become very minimal or as small as possible.
For any least-squares regression line, the sum of the residuals is always zero.
Basically, residuals are used to measure or determine whether or not the line of regression is a good fit or match for the data by subtracting the difference between them i.e the predicted y value and the actual y value, for the x value respectively.
Hence, the statement about residuals which is true for the least-squares regression line is that the sum of the residuals is always zero (0).
Answer:
Step-by-step explanation:
There is an error in the question. The table does not show two linear functions. y₁ is a linear function, but y₂ is not a straight line. It makes a bend at (-6,1).
Line 1 goes through (-12,-3) and (0,5).
slope = (5-(-3))/(0-(-12)) = 2/3
y-intercept = 5
y₁ = (2/3)x + 5
Line 2 goes through (-12,-2) and (-6,1).
slope = (1-(-2))/(-6-(-12)) = 1/2
y₂ = (1/2)x + 4
(2/3)x + 5 = (1/2)x + 4
x = -6
y = (2/3)x + 5 = 1
Solution: (-6,1)
