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____ [38]
3 years ago
7

What's the value of

\times 1} " alt=" \sqrt{25 \times 1} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Yuki888 [10]3 years ago
8 0

Answer:

5

Step-by-step explanation:

\sqrt{25*1}= \sqrt{25}

\sqrt{25}=5

Square root of 25 is 5, because 5x5=25.

Marizza181 [45]3 years ago
6 0
Your answer is:

5

Hope it helps :D
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Step-by-step explanation:

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7 0
3 years ago
Solve the equation.<br><br> (8x3−9)3=5832
marishachu [46]
If you have a Scientific calculator you can type this in
5 0
2 years ago
Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is   P(A' n B' ) = 0.8855

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A  is  P(A' n B) =0.0403

Step-by-step explanation:

From the question we are told that

   The sample size is n_s =  10000

    The number of outcome for inspector A is  n__{A}} = 742

    The number of outcome for inspector B is  n__{B}} = 745

     The number of joints judged defective by both inspector is n(A u B) =  1145

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

      P(A' n B' ) =  1 - P(A u B)

Now

       P(A\ u \ B) = \frac{n(Au B)}{n_s }

substituting values

        P(A\ u \ B) = \frac{1145}{ 10 000 }

So  

      P(A' n B' ) =  1 - \frac{1145}{10 000}

     P(A' n B' ) = 0.8855

the probability that the selected joint was judged to be defective by inspector B but not by inspector A  is mathematically represented as

     P(A' n B) =  P(A \ u \ B) -P(A)

Now

        P(A) =  \frac{n__{A}}{n_s}

substituting values

       P(A) =  \frac{742}{10 000}

So

     P(A' n B) =   \frac{1145}{10 000}  - \frac{742}{10 000}

    P(A' n B) =0.0403

7 0
3 years ago
Rachel weighed her two cats, Tiger and Mittens. Tiger weighed 10.91 pounds, and Mittens weighed 178.08 ounces. Which cat is heav
Dafna11 [192]

Answer:

answer is c

Step-by-step explanation:

178.08 oz = 11.13 lb

11.13-10.91 = 0.22 lb

4 0
2 years ago
Solve for substitution 8x+2y=13 and 4x+y=11
damaskus [11]
Solving for X:
1) y=-8x+6.5   y=-4x+11
2) -8x+6.5=-4x+11
3) -8x=-4x+11-6.5        (Subtract 6.5 from both sides)
4) -8x+4x=11-6.5         (Add 4x to both sides)
5)-4x=4.5
5)x=-1.125

Solving for Y:
y=-8(-1.125)+6.5
y=9+6.5
y=15.5

y=-4(-1.125)+11
y=4.5+11
y=15.5

x=-1.125
y=15.5
or
(-1.125,15.5)
7 0
3 years ago
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