Question

What is the sum of the favorable and unfavorable probabilities?

Answer 1

The sum of the favorable and unfavorable probabilities for event x is $-x^{2} +x+ 1$ .

Step-by-step explanation:

A favorable outcome is the outcome that you are looking for in an experiment. Theoretical Probability. The theoretical probability of an event is the likelihood that the event will occur.

Here there's no sample space , nor any case given . We need to find the sum of the favorable and unfavorable probabilities . Let's find out:

Let , If we say probability as $p(x=1)=x$  , so $p(x\neq 1) = 1-x$ . Now sum of favorable & unfavorable probabilities is given by:

⇒ $p(x=1) + p(x=1)(p(x\neq 1)) + p(x\neq 1)$

⇒ $(x) + x(1-x) + (1-x)$

⇒ $x + x-x^{2} + 1-x$

⇒ $x -x^{2} + 1$

⇒ $-x^{2} +x+ 1$ , where x is the event happening !

Answer 2

1

Step-by-step explanation:

Step 1:

Let a coin is flipped. My choice is Heads and my unfavorable becomes  Tails.

Here the probability of getting heads is (1/2) and getting tails is (1/2).

Step 2:

Hence, If we add both of it we will get the resultant sum as 1 only.

(1/2) + (1/2) = 1