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trapecia [35]
2 years ago
10

The back of Tom's property is a creek. Tom would like to enclose a rectangular area, using the creek as one side and fencing

Mathematics
1 answer:
Anna71 [15]2 years ago
8 0

9514 1404 393

Answer:

  1250 square feet

Step-by-step explanation:

If x is the length of the side perpendicular to the creek, then the third side is (100 -2x) = 2(50 -x). The area is the product of length and width:

  A = x(2)(50-x)

We observe that this is a quadratic function with zeros at x=0 and x=50. The vertex (maximum) of a quadratic function is on the line of symmetry, halfway between the zeros. The value of x there is (0 +50)/2 = 25.

Then the maximum area is ...

  A = (25)(2)(50 -25) = 1250 . . . . square feet

_____

<em>Additional comment</em>

Note that half the length of the fence is used in one direction (parallel to the creek), and half is used in the other direction (perpendicular to the creek). This 50/50 split is the generic solution to all sorts of rectangular corral problems, with or without a creek, with or without internal partitions.

Half the fence is perpendicular to the other half. (If the costs are different in different directions, then the cost is what is split 50/50.)

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Step-by-step explanation:

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5 0
2 years ago
Paul is two years younger than Patricia. Daniel is 25% older than Patricia. Ten years ago, Daniel was 50% older than Patricia. H
Sergeeva-Olga [200]

We have 3 people: Paul, Daniel and Patricia. Let each name denote that person’s current age in years. Remember that % is the symbol for 1/100.


PAUL: (#A) Paul = Patricia – 2
DANIEL: 
(#B) Daniel = 125% * Patricia = 125 * (1/100) * Patricia = 1.25 * Patricia
(#C) Ten years ago, Daniel’s age at that time would have been Daniel’s current age – 10. IE “Daniel – 10”.
Ten years ago, Patricia’s age at that time would have been Patricia’s current age – 10. IE “Patricia – 10”. 
Ten years ago, Daniel’s age at that time (IE Daniel – 10) was 50% greater than Patricia’s age at the time (Patricia – 10). 
IE 

Daniel – 10 = 150% * (Patricia – 10)
Daniel – 10 = 1.50 * (Patricia – 10)
Daniel – 10 = 1.50 * Patricia – 1.50 * 10
Daniel – 10 = 1.50 * Patricia – 15
Daniel = 1.50 * Patricia – 15 + 10
Daniel = 1.50 * Patricia – 5


So now we have 3 equations in 3 unknowns:
(A) Paul = Patricia – 2
(B) Daniel = 1.25 * Patricia
(C) Daniel = 1.50 * Patricia – 5


Solve equations B & C simultaneously
 1.25 * Patricia = 1.50 * Patricia – 5
 1.25 * Patricia – 1.50 * Patricia = – 5
– 0.25 * Patricia = – 5
 Patricia = (– 5) / (– 0.25) 
Patricia = + 20

So now we can write the 3 people’s ages:
(a) Patricia = 20
(b) Paul = Patricia – 2 = 20 – 2 = 18
(c) Daniel = 1.25 * Patricia = 1.25 * 20 = 25

<span>
</span>

<span>Finally, we check our solution against the original question. </span>
Paul is two years younger than Patricia. ……… 20 – 2 = 18 ✔
Daniel is 25% older than Patricia. ……… 25 = 125% * 20 ✔
Ten years ago, Daniel was 50% older than Patricia. 25 – 10 = 150% (20– 10) ✔


Hope that helped :)

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