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Xelga [282]
2 years ago
6

Describe fully the single transformation that maps triangle A onto triangle B. please help ASAP​

Mathematics
1 answer:
kupik [55]2 years ago
5 0
Hi how you doing? “Be safe”
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Which fraction, in lowest terms, is equivalent to the decimal 0.5?
BARSIC [14]

Answer:

1/2

Step-by-step explanation:

The decimal 0.5 is equal to the fraction 1/2.

it can also be, 0.5 represent the fraction 5/10.

8 0
3 years ago
Read 2 more answers
1.) What is the best approximation of the solution to the system to the nearest integer values?
melisa1 [442]

<u>Part 1)</u> we have

5x+2y=16 ------> equation A

x+3y=12

x=12-3y ------> equation B

Substitute the equation B in equation A

5[12-3y]+2y=16

60-15y+2y=16

13y=44

y=44/13=3.38

Find the value of x

x=12-3(44/13)=1.85

the best approximation is the point (2.3)

therefore

<u>the answer Part 1) is the option C</u>

(2.3)

<u>Part 2) </u>we have

y=-x-2 ------> equation A

y=3x+2 ------> equation B

equate equation A and equation B

-x-2=3x+2

4x=-4

x=-1

Find the value of y

y=-(-1)-2=-1

the solution is the point (-1,-1)

therefore

<u>the answer Part 2) is </u>

(-1,-1)


5 0
3 years ago
Read 2 more answers
The product of three and a square number is twice the sum of the number and four
alex41 [277]
Write an equation, calling the number x:

3x=2(x+4)

3x=2x+8

x=8

However, 8 is not a perfect square, which was required in the problem, so there are no solutions.
5 0
3 years ago
Simplify the expression
ollegr [7]

Answer:

<h3>              f(x) = x - 6</h3><h3>             g(x) = x - 5</h3>

Step-by-step explanation:

\dfrac{x^2-8x+12}{x^2-7x+10}\\\\x^2-7x+10\ne0\ \iff\ x=\frac{7\pm\sqrt{49-40}}{2}\ne0\ \iff\ x\ne5\ \wedge\ x\ne2\\\\\\\dfrac{x^2-8x+12}{x^2-7x+10}=\dfrac{x^2-2x-6x+12}{x^2-2x-5x+10}=\dfrac{x(x-2)-6(x-2)}{x(x-2)-5(x-2)}=\\\\\\ =\dfrac{(x-2)(x-6)}{(x-2)(x-5)}=\dfrac{x-6}{x-5}\\\\\\f(x)=x-6\\\\g(x)=x-5

4 0
3 years ago
Use the zero product property to find the solutions to the equation 2x2 + x-1 = 2
algol [13]

Answer:

see explanation

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - \frac{3}{2}

3 0
3 years ago
Read 2 more answers
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