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3 years ago

PLEASE HELP LATS MATH PROBLEM A, B and C

Mathematics

1 answer:

Llana [10]3 years ago

8 0

Answer:

a) Set up triangles where the hypotenuse is 16ft (the ladder) and one of the two edges are 1, 2, 3, 4, 5ft (the base of the ladder). Use a^2 + b^2 = c^2 where a is the base length, c is the hypotenuse and b is the value you are trying to find.

Ex w/ 1ft base:

1^2 + b^2 = 16^2

1 + b^2 = 256

b^2 = 255

b = 15.97ft.

b) Simply take your answers from part a) and add 5.5ft (the height of the girl) to them.

Ex w/ 1ft base:

15.97ft + 5.5ft = 21.47ft

c) Using logic here think about it. Let's take the 1ft base as the example. Marissa standing on top of the ladder is 21.47ft. That's clearly not high enough to reach the cat . . . but what happens if Marissa reaches upwards. As long as her arms can reach roughly 1.53ft above her head she should be able to reach it.

Step-by-step explanation:

lolz

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What criteria must a polygon meet to be considered inscribed in a circle? <br> Help ASAP!!

Monica [59]

A polygon is inscribed in a circle if all its vertices are points on the circle and all sides are included within the circle. All regular polygons can be inscribed in a circle. The center of an inscribed polygon is also the center of the circumscribed circle.

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3 years ago

Read 2 more answers

Find the work required to move an object in the force field F = ex+y <1,1,z> along the straight line from A(0,0,0) to B(-1

storchak [24]

Answer:

Work = e+24

F is not conservative.

Step-by-step explanation:

To find the work required to move an object in the force field

$\large F(x,y,z)=(e^{x+y},e^{x+y},ze^{x+y})$

along the straight line from A(0,0,0) to B(-1,2,-5), we have to parameterize this segment.

Given two points P, Q in any euclidean space, you can always parameterize the segment of line that goes from P to Q with

r(t) = tQ + (1-t)P with 0 ≤ t ≤ 1

r(t) = t(-1,2,-5) + (1-t)(0,0,0) = (-t, 2t, -5t) with 0≤ t ≤ 1

is a parameterization of the segment.

the work W required to move an object in the force field F along the straight line from A to B is the line integral

$\large W=\int_{C}Fdr$

where C is the segment that goes from A to B.

$\large \int_{C}Fdr =\int_{0}^{1}F(r(t))\circ r'(t)dt=\int_{0}^{1}F(-t,2t,-5t)\circ (-1,2,-5)dt=\\\\=\int_{0}^{1}(e^t,e^t,-5te^t)\circ (-1,2,-5)dt=\int_{0}^{1}(-e^t+2e^t+25te^t)dt=\\\\\int_{0}^{1}e^tdt-25\int_{0}^{1}te^tdt=(e-1)+25\int_{0}^{1}te^tdt$

Integrating by parts the last integral:

$\large \int_{0}^{1}te^tdt=e-\int_{0}^{1}e^tdt=e-(e-1)=1$

and

$\large \boxed{W=\int_{C}Fdr=e+24}$

To show that F is not conservative, we could find another path D from A to B such that the work to move the particle from A to B along D is different to e+24

Now, let D be the path consisting on the segment that goes from A to (1,0,0) and then the segment from (1,0,0) to B.

The segment that goes from A to (1,0,0) can be parameterized as

r(t) = (t,0,0) with 0≤ t ≤ 1

so the work required to move the particle from A to (1,0,0) is

$\large \int_{0}^{1}(e^t,e^t,0)\circ (1,0,0)dt =\int_{0}^{1}e^tdt=e-1$

The segment that goes from (1,0,0) to B can be parameterized as

r(t) = (1-2t,2t,-5t) with 0≤ t ≤ 1

so the work required to move the particle from (1,0,0) to B is

$\large \int_{0}^{1}(e,e,-5et)\circ (-2,2,-5)dt =25e\int_{0}^{1}tdt=\frac{25e}{2}$

Hence, the work required to move the particle from A to B along D is

e - 1 + (25e)/2 = (27e)/2 -1

since this result differs from e+24, the force field F is not conservative.

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4 years ago

Complex numbers are used in electronics to describe the current in an electric circuit. Ohm's law relates the current in a circu

Marina CMI [18]

Answer:

E = 3072i - 5904ohms

Step-by-step explanation:

From ohms law recalled that E = IR given already

E = voltage (volts)

I = Current (amps)

R = resistance (ohms)

Therefore, by substitution

I = 16i and R = (2+4)ohms(32+66i)

= 6(32+66i) ohms

= (192+396i)ohms

E = (16i)×(192+396i)

E = 3072i + 5904i²

Recall that i² = -1 from complex number

E = 3072i +5904(-1)

E = 3072i - 5904ohms

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3 years ago

The circle will be enlarged by a scale factor of 4.

sertanlavr [38]

Answer:

The area of the new circle is $144\pi \ in^2$

Step-by-step explanation:

Given:

radius of the circle = 3 in.

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared.

Let

z-----> the scale factor

x-----> the area of the enlarged circle

y-----> the area of the original circle

So;

$z^2= \frac{x}{y}$

In this problem we have

$z=4$ ----> the scale factor

The area of the original circle is equal to

$y = \pi r^2= \pi (3)^2= 9\pi \ in^2$

Now substituting value of y and solve for x we get;

$4^2=\frac{x}{9\pi}\\ \\x= 16\times9\pi= 144\pi \ in^2$

Hence Area of the new Circle is $144\pi \ in^2$

Also The area of the enlarged circle is 16 times the area of the original circle.

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4 years ago

What is the value of this expression <br> 3 x 5 (5+5) =

Agata [3.3K]

You would do 5+5 first then 10+3x5 which equals 25.

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3 years ago