4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2
5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3
6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
Answer:
The probability that the sum of the numbers rolled is either a multiple of 3 or an even number is 24/36 = 2/3
The two events are mutually exclusive
Step-by-step explanation:
we first need to create a table of the sample space from the experiment, the sum of the numbers rolled. Find the attached for a depiction of the possible outcomes.
The probability that the sum of the numbers rolled is either a multiple of 3 or an even number will be given by counting the numbers that are either even or multiples of 3 and then dividing by the number of possible outcomes, 36.
In our case this will be;
24/36 = 2/3
No se si esté correcto, buena suerte!:)
Answer:
X= -45
Step-by-step explanation:
Subract 23 from both sides to solve for x.
Answer:
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Step-by-step explanation: