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grin007 [14]
3 years ago
8

5(x+4)= -2(-4-x)+3 what is the answer?

Mathematics
2 answers:
lianna [129]3 years ago
5 0

Answer:

x = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

5(x + 4) = -2(-4 - x) + 3

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   5x + 20 = 8 + 2x + 3
  2. Combine like terms:                   5x + 20 = 2x + 11
  3. Subtract 2x on both sides:        3x + 20 = 11
  4. Subtract 20 on both sides:        3x = -9
  5. Divide 3 on both sides:              x = -3

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    5(-3 + 4) = -2(-4 - -3) + 3
  2. Simplify:                        5(-3 + 4) = -2(-4 + 3) + 3
  3. Add:                              5(1) = -2(-1) + 3
  4. Multiply:                        5 = 2 + 3
  5. Add:                              5 = 5

Here we see that 5 does indeed equal 5. ∴ x = -3 is a solution of the equation.

And we have our final answer!

Travka [436]3 years ago
5 0

Answer:

x=-3

Step-by-step explanation:

first multiply them out: 5x+20=2x+11

then subtract both sides by 2x: 3x+20=11

subtract both sides by 20: 3x=-9

divide both sides by 3: x=-3

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UNA POBLACION DE CIERTA CIUDAD EN EL AÑO 2000 ERA DE 250,000 HABITANTES CON UNA TASA DE CRECIMIENTO RELATIVO DEL 2% , DETERMINA
Fofino [41]

Answer:

La población que se espera para el 2012, es 317,060

Step-by-step explanation:

Si la población tiene un crecimiento relativo del 2%, entonces cada año, la población es un 2% más grande que el año anterior.

Definamos P(t) = población después de t años

Entonces, si al año t = 0 (que corresponde con el año 2000) la población es A

P(0) = A

Un año después, en t = 1, la población incrementa en un 2%

P(1) = A + (2%/100%)*A = A + (0.02)*A = A*(1.02)

Otro año después, en t = 2, la población incrementa un 2% de vuelta.

P(2) = A*(1.02) + (2%/100%)*A(1.02) = A*(1.02) + 0.02*A*(1.02)

      = A*(1.02)*(1.02) = A*(1.02)^2

Ya podemos notar un patrón, la población en el año t va a ser:

P(t) = A*(1.02)^t

Sabemos que en t = 0 (el año 2000) la población es 250,000

Entonces A = 250,000

P(t) = 250,000*(1.02)^t

Ahora queremos calcular la población en el año 2012

entonces si t = 0 es el 2000

2012 esta representado con t = 12

Reemplazando eso en la ecuación, obtenemos:

P(12) = 250,000*(1.02)^12 = 317,060.4

Como esto es una población tenemos que redondearlo al próximo número entero, como el primer digito después del punto es 4, redondeamos para abajo.

Entonces la población que se espera para el 2012 es: 317,060

5 0
2 years ago
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